CODEWITHSUNDEEP
gulpgulp-watch
Gili
Gili

Reputation: 90101

Declaring optional dependencies

Given:

gulp.task("watch", function()
{
  // Asynchronous execution
  return gulp.src("...").
    doSomething1();
});

gulp.task("default", function()
{
    // Synchronous execution
    doSomething2();
    doSomething3();
});

gulp.task("css", ["csslint"]);

I would like css to run after default or watch completes but I can't declare default or watch as dependencies because that would trigger their execution.

How do I declare an optional dependency? (run css after default or watch if they are already scheduled for execution, but don't schedule their execution).

Upvotes: 1

Views: 552

Answers (1)

Josh Kodroff
Josh Kodroff

Reputation: 28141

I don't believe gulp supports the concept of optional dependencies. I believe what you need is run-sequence. It'll allow you to do this:

var sequence = require('run-sequence');

gulp.task('mySequence', sequence(
  ['task1', 'task2'], // ok to run these in parallel
  'task3' // will not run until 1 and 2 are both completed
));

It looks like gulp v4 will address this shortcoming.

Upvotes: 1

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