CODEWITHSUNDEEP
pythonstringpython-3.x
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Reputation: 13

How to make string into permutation?

So the assignment I was given was to create a function that takes x as an argument which assigns numbers according to (what I assume to be) the inputted letter's ordinal values. Keep in mind that only non-repeating lowercase letters are to be inputted.

Since "a < b", and "a < c", if I were to input a string "abc" into this function, it should return '123'. If I inputted "zad", it should return "312". In other words, smallest letter starts at 1, the next smallest, 2, etc.

How should I go about construction a function that fits this criteria? I figured I would include a range going from ord[a] to ord [z] and then include an elif loop statement. Any pointers?

Upvotes: 0

Views: 76

Answers (2)

GLHF
GLHF

Reputation: 4035

str1 = "bca"
print (sorted([str1.index(x)+1 for x in sorted(str1)]))

Sort them first and print sorted index of them. Carefull, +1 to index, because index starting from 0.

Upvotes: 0

Juan Lopes
Juan Lopes

Reputation: 10565

You can construct a dictionary that maps each character to its position in the sorted list of the distinct characters in the original string:

def perm(s):
    indexes = {x:i+1 for i,x in enumerate(sorted(set(s)))}
    return ''.join(str(indexes[x]) for x in s)

print(perm('abc'))
print(perm('zad'))

Upvotes: 2

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