Reputation: 29
I want to swap numbers of four digits number that enter users. And I wrote that codes
private void btnSwap_Click(object sender, EventArgs e)
{
int number, digit1, digit2, digit3, digit4;
number = Convert.ToInt32(txtNumber.Text);
digit1 = number % 10;
digit2 = (number / 10) % 10;
digit3 = (number / 100) % 10;
digit4 = (number / 1000) % 10;
digit4 = digit1;
digit1 = digit3;
digit3 = digit2;
digit2 = digit1;
lbReserved.Text = number.ToString();
}
But that codes return same number ? How to do it?
Upvotes: 0
Views: 1213
Reputation: 460068
Theay are already reversed due to your maths, no need to swap the variables. So you just need to create a new int if you want:
int reversedNumber = int.Parse(string.Concat(digit1, digit2, digit3, digit4));
If you want an even more concise version without maths:
int reversedNumber = int.Parse(string.Concat(txtNumber.Text.TrimStart('0').Reverse()));
Upvotes: 1
Reputation: 1
You can do it swapping chars of string recursively.
Here's the example.
private void btnSwap_Click(object sender, EventArgs e)
{
string number = txtNumber.Text;
lbReserved.Text = reverseString(number);
}
private string reverseString(string str)
{
string result = "";
if (str.length() == 1)
{
result = str;
}
else
{
result += str.charAt(str.length() - 1) + reverseString(str.substring(0, str.length() - 1));
}
return result;
}
Upvotes: 0