CODEWITHSUNDEEP
debuggingandroid-studiobreakpoints
Adam
Adam

Reputation: 10016

Determine value of variables at hit breakpoint in Android Studio

...
BREAKPOINT `int i = 10 + 12;`
...

When I add a break point to code in Android Studio as above, AS will run to the line I added the break point to, as expected. However, if there is no code after the break point line I can't see what i resolves to in the debugger. I can fix this problem by inserting a single line of dummy code, but there must be an easier/more elegant way to get around this problem that I'm missing.

How can I avoid adding a dummy line of code to view these values?

EDIT: I'm using the latest version of Android Studio (1.0.2)

Upvotes: 2

Views: 2139

Answers (1)

CJBS
CJBS

Reputation: 15685

It's possible to put a breakpoint on the line following the last line you want executed.

A breakpoint stops execution before the line under the breakpoint is executed.

In the example above, a new variable is introduced (i), which is as yet unknown to the interpreter. It's necessary to step-over (execute) the line of code in order for this variable to be initialized.

See the example below, in which there's a test function that contains the line of code from the question:

Hit breakpoint

I've put breakpoints on the start brace of the function {, the line in question, and the end brace }. Note that there's an X on the first breakpoint, as it's invalid. The current execution point is on (or just before execution of) the dark-blue highlited line. Note that the variable i does not exist in the Variables window below.

When I step over (execute) the line of code, the active line is now over the final brace in the function }, and that the variable i is now initialized and set:

At final brace in function

So, if you're interested in breaking after a given line of code, just put the breakpoint after that line of code, even if that line is the final brace of a function.

Note: this won't work if there is an exit statement (e.g. break, return etc.) as the final executed line of code in a function.

Upvotes: 2

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