CODEWITHSUNDEEP
pythondictionary
Bilel_a
Bilel_a

Reputation: 163

compare two dictionaries in python

How do i campare dictionaries that contain dictionaries ?

This will work in case the dictionaries contain simple values 

# will show the keys with different values

d1_keys = set(dict1.keys())
d2_keys = set(dict2.keys())
intersect_keys = d1_keys.intersection(d2_keys)
modified = {}
for i in intersect_keys:
     if dict1[i] != dict2[i] : modified.update({i : (dict1[i], dict2[i])})

but i have a dictionary like this:

{ 'medic1' : {'date' : '02/02/2015', 'no' : '123' }, 'medic2' : {'date' :'02/03/2015', 'no' : '456' }}

Upvotes: 0

Views: 7310

Answers (2)

Vivek Sable
Vivek Sable

Reputation: 10213

By recursion function for nested dictionary.

  1. Get common keys from both dictionary by keys() and set operation.
  2. Iterate common keys by for loop.
  3. Check type of value of key is dict or not.
  4. If value type is dict then call same function and pass values dictionary as arguments. and add result as key into modified dictionary.
  5. If value type is not dict then add into modified dictionary.

code:

dict1 = { 
        'medic1' : {'date' : '02/02/2015', 'no' : '123' }, 
        'medic2' : {'date' : '02/03/2015', 'no' : '456' },
        'testkey1': 'testvalue1',
        'testkey2': 'testvalue2',
        'testkey3':{ "level2_1":"value2_1", 
            "level2_2":{ 
                        "level3_1": "value3_1_change", 
                        "level3_2": "value3_2", 
                    }
        }
}

dict2 = { 
        'medic1' : {'date' : '02/02/2015', 'no' : '456' }, 
        'medic2' : {'date' : '02/03/2015', 'no' : '456' },
        'testkey1': 'testvalue1',
        'testkey2': 'testvalue22',
        'testkey3':{ "level2_1":"value2_1", 
                    "level2_2":{ 
                                "level3_1": "value3_1", 
                                "level3_2": "value3_2", 
                            }
                }

}

import copy

def compareDict(dict1, dict2):

    d1_keys = dict1.keys()
    d2_keys = dict2.keys()
    intersect_keys = set(d1_keys).intersection(set(d2_keys))
    modified = {}
    for i in intersect_keys:
        if dict1[i] != dict2[i] : 
            if isinstance(dict1[i], dict) and isinstance(dict1[i], dict):
                modified[i]=compareDict(dict1[i], dict2[i])
            else:
                modified.update({i : (dict1[i], dict2[i])})

    return copy.deepcopy(modified)


modified = compareDict(dict1, dict2)
import pprint
pprint.pprint(modified)

output:

vivek@vivek:~/Desktop/stackoverflow$ python 5.py 
{'medic1': {'no': ('123', '456')},
 'testkey2': ('testvalue2', 'testvalue22'),
 'testkey3': {'level2_2': {'level3_1': ('value3_1_change', 'value3_1')}}}

Upvotes: 5

Alex Martelli
Alex Martelli

Reputation: 881555

As long as the keys are hashable (which a dict guarantees!-) it doesn't matter whether the values are or not -- code like:

common_keys = set(dict1).intersection(dict2)

(a simplified version of your first three lines), then

modified = {k: (dict1[k], dict2[k])
            for k in common_keys if dict1[k] != dict2[k]}

(a simplified version of your last three lines) will work fine!

Upvotes: 1

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