CODEWITHSUNDEEP
bashshellawksedoutput
user3344218
user3344218

Reputation: 57

How do you send output of argument to another argument

I want to create a script that needs to take 3 arguments. I want to send the output of the first argument to the second argument and then redirect the final output to a new final. How would I go about doing this?

Upvotes: 0

Views: 49

Answers (1)

Jose Martinez
Jose Martinez

Reputation: 11992

You can create a script that takes three arguments and from within that script you call you three other commands passing each command one of the arguments.

You would use the script like this:

./mainScript.sh "arg1" "arg 2" "arg3"

Inside the script it would look like this:

#!/bin/bash

commandOne "$1"
commandTwo "$2"
commandThree "$3"

THis is a very simple example. Production ready code would validate the number of arguments like this

if [ "$@" -ne "3" ]
then 
    echo "must provide three arguments"
    exit
fi

Upvotes: 1

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