CODEWITHSUNDEEP
pythoncharactercount
Rachel Green
Rachel Green

Reputation: 47

Count characters in string

So I'm trying to count anhCrawler and return the number of characters with and without spaces alone with the position of "DEATH STAR" and return it in theReport. I can't get the numbers to count correctly either. Please help!

anhCrawler = """Episode IV, A NEW HOPE. It is a period of civil war. \
Rebel spaceships, striking from a hidden base, have won their first \
victory against the evil Galactic Empire. During the battle, Rebel \
spies managed to steal secret plans to the Empire's ultimate weapon, \
the DEATH STAR, an armored space station with enough power to destroy \
an entire planet. Pursued by the Empire's sinister agents, Princess Leia\
races home aboard her starship, custodian of the stolen plans that can \
save her people and restore freedom to the galaxy."""

theReport = """
This text contains {0} characters ({1} if you ignore spaces).
There are approximately {2} words in the text. The phrase
DEATH STAR occurs and starts at position {3}.
"""

def analyzeCrawler(thetext):
numchars = 0
nospacechars = 0
numspacechars = 0
anhCrawler = thetext
word = anhCrawler.split()
for char in word:
    numchars = word[numchars]
    if numchars == " ":
        numspacechars += 1
anhCrawler = re.split(" ", anhCrawler)
for char in anhCrawler:
    nospacechars += 1
numwords = len(anhCrawler)
pos = thetext.find("DEATH STAR")
char_len = len("DEATH STAR")
ds = thetext[261:271]
dspos = "[261:271]"

return theReport.format(numchars, nospacechars, numwords, dspos)
print analyzeCrawler(theReport)

Upvotes: 0

Views: 3898

Answers (3)

Eithos
Eithos

Reputation: 2491

First off, you need to indent the code that's inside a function. Second... your code can be simplified to the following:

theReport = """
    This text contains {0} characters ({1} if you ignore spaces).
    There are approximately {2} words in the text. The phrase
    DEATH STAR is the {3}th word and starts at the {4}th character.
"""

def analyzeCrawler(thetext):

    numchars = len(anhCrawler)
    nospacechars = len(anhCrawler.replace(' ', ''))
    numwords = len(anhCrawler.split())

    word = 'DEATH STAR'
    wordPosition = anhCrawler.split().index(word)
    charPosition = anhCrawler.find(word)

    return theReport.format(
        numchars, nospacechars, numwords, wordPosition, charPosition
    )

I modified the last two format arguments because it wasn't clear what you meant by dspos, although maybe it's obvious and I'm not seeing it. In any case, I included the word and char position instead. You can determine which one you really meant to include.

Upvotes: 1

jrd1
jrd1

Reputation: 10726

You're overthinking this problem.

Number of chars in string (returns 520):

len(anhCrawler)

Number of non-whitespace characters in string (using split as using split automatically removes the whitespace, and join creates a string with no whitespace) (returns 434):

len(''.join(anhCrawler.split()))

Finding the position of "DEATH STAR" (returns 261):

anhCrawler.find("DEATH STAR")

Upvotes: 2

Marcin
Marcin

Reputation: 239005

Here, you have simplilfied version of your function:

import re

def analyzeCrawler2(thetext, text_to_search = "DEATH STAR"):

    numchars = len(anhCrawler)
    nospacechars = len(re.sub(r"\s+", "", anhCrawler))
    numwords   = len(anhCrawler.split())
    dspos      =  anhCrawler.find(text_to_search)

    return theReport.format(numchars, nospacechars, numwords, dspos)



print analyzeCrawler2(theReport)


This text contains 520 characters (434 if you ignore spaces).
There are approximately 87 words in the text. The phrase
DEATH STAR occurs and starts at position 261.

I think the trick part is to remove white spaces from the string and to calculate the non-space character count. This can be done simply using regular expression. Rest should be self-explanatory.

Upvotes: 1

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