CODEWITHSUNDEEP
c++c++11tuples
AlphaRL
AlphaRL

Reputation: 1629

c++ : convert vector to tuple

How can I convert std::vector to std::tuple ? I have 

class T { };
int cnt = 3;
vector<T*> tv;
for (int i = 0; i < cnt; ++i) {
  tv.push_back(new T());
}

I want to get

auto tp = std::tie(*tv[0], *tv[1], *tv[2]);

How can I get this tp ? If cnt is big enough, I can't write this tp manually.

  std::vector<
  ConvConnection<
  decltype(inputLayer),
  decltype(*C1[0]),
  decltype(*Conn1Opt[0]),
  RandomInitialization<arma::mat>,
  arma::mat
  >* > Conn1(6);

  for (size_t i = 0; i < 6; ++i) {
    Conn1.push_back(new  ConvConnection<
                    decltype(inputLayer),
                    decltype(*C1[0]),
                    decltype(*Conn1Opt[0]),
                    RandomInitialization<arma::mat>,
                    arma::mat
                    >(inputLayer, *C1[i], *Conn1Opt[i], 5, 5));
  }

This is the code. Here is just 6, but I also need some vector whose size is over 100. I need to convert this vector to a tuple.

Upvotes: 13

Views: 16528

Answers (3)

Barry
Barry

Reputation: 302787

Generally, you cannot convert a vector to a tuple. However, if all you're trying to do is make the tuple <f(0), f(1), ..., f(N-1)> for some N that is a constant-expression, then that is doable with the index sequence trick:

template <typename F, size_t... Is>
auto gen_tuple_impl(F func, std::index_sequence<Is...> ) {
    return std::make_tuple(func(Is)...);
}

template <size_t N, typename F>
auto gen_tuple(F func) {
    return gen_tuple_impl(func, std::make_index_sequence<N>{} );
}

Which we can use like:

// make a tuple of the first 10 squares: 0, 1, 4, ..., 81
auto squares = gen_tuple<10>([](size_t i){ return i*i;});

For your specific use-case, that would be:

auto connections = gen_tuple<6>([&](size_t i) {
    return new ConvConnection<
                decltype(inputLayer),
                decltype(*C1[0]),
                decltype(*Conn1Opt[0]),
                RandomInitialization<arma::mat>,
                arma::mat
                >(inputLayer, *C1[i], *Conn1Opt[i], 5, 5);
});

Upvotes: 19

Sebastian Redl
Sebastian Redl

Reputation: 71909

If you have C++14, you can do it like this:

template <typename T, std::size_t... Indices>
auto vectorToTupleHelper(const std::vector<T>& v, std::index_sequence<Indices...>) {
  return std::make_tuple(v[Indices]...);
}

template <std::size_t N, typename T>
auto vectorToTuple(const std::vector<T>& v) {
  assert(v.size() >= N);
  return vectorToTupleHelper(v, std::make_index_sequence<N>());
}

Thanks to auto deduction, this is ok. In C++11, without auto deduction, you have to write the return types with trailing decltype. You also have to implement your own index_sequence.

Upvotes: 18

bolov
bolov

Reputation: 75688

You just can't. Because the vector size is known at runtime, but tuple type (which includes its size) must be known at compile time.

Upvotes: 6

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