CODEWITHSUNDEEP
javajpaplayframeworkplayframework-2.2playframework-2.3
Mornor
Mornor

Reputation: 3803

Use save() method in Play! with inheritance (JPA)

I have my super abstract class : 

@Entity
@Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)
public abstract class User {

    @Id
    public int id; 
    public String name; 
}

And two other classes extends User:

Customer

@Entity
@Table(name = "customers")
public class Customer extends User{

    @Id
    public int id; 
    public String role; 

    public Customer(String role){
        super(); 
        this.role = role; 
    }
}

Seller

@Entity
@Table(name = "sellers")
public class Seller extends User{

    @Id
    @GeneratedValue
    public int id; 
    public String role; // Seller

    public Seller(String role){
        super(); 
        this.role = role; 
    }
 }

I would like to be able to use the save() method in play, so I wrote this :

public static Result saveCustomer(){
        Customer customer = Form.form(Customer.class).bindFromRequest().get();
        customer.save();        
        return ok(); 
    }

But, save() is not defined.

What would be the way to solve this issue ?

Upvotes: 1

Views: 328

Answers (2)

Santiago Ferrer Deheza
Santiago Ferrer Deheza

Reputation: 312

Actually... to get the entityManager in play 2.x you hava a Helper.

JPA.em().persist(object);

you can see more information in this link.

Upvotes: 1

Mon Calamari
Mon Calamari

Reputation: 4463

save() method is a part of GenericModel which belongs to Play 1.x. Since, you use Play 2.x you should use JPA object and entityManager.persist() method.

Upvotes: 0

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