CODEWITHSUNDEEP
xmlbashcsvexport-to-csv
user3319356
user3319356

Reputation: 173

Xml file to CSV output

I have xml file, which is in format as below, and I want to transform it in csv otput as shown below. Unfortunatly I'm not allowed to install xmlstarlet or some other xml parser (I have only xmllint). How can I do this, for example with, awk, sed....

     <xn:VsDataContainer id="site00881">
                            <es:listOfNe>SubNetwork=NL1_R,SubNetwork=AHPTUR14,MeContext=rbs008811,ManagedElement=1</es:listOfNe>
                            <es:listOfNe>SubNetwork=NL1_R,SubNetwork=AHPTUR14,MeContext=rbs008819,ManagedElement=1</es:listOfNe>
                </xn:VsDataContainer>
                <xn:VsDataContainer id="site00882">
                            <es:listOfNe>SubNetwork=NL1_R,SubNetwork=AHPTUR14,MeContext=rbs008821,ManagedElement=1</es:listOfNe>

<es:listOfNe>SubNetwork=NL1_R,SubNetwork=AHPTUR14,MeContext=rbs008829,ManagedElement=1</es:listOfNe>
                </xn:VsDataContainer>
                <xn:VsDataContainer id="site00883">
                            <es:listOfNe>SubNetwork=NL1_R,SubNetwork=ASDTUR13,MeContext=rbs008831,ManagedElement=1</es:listOfNe>
                            <es:listOfNe>SubNetwork=NL1_R,SubNetwork=ASDTUR_SIU,MeContext=siu008832,ManagedElement=siu008832</es:listOfNe>
                </xn:VsDataContainer>
                <xn:VsDataContainer id="site00884">
                            <es:listOfNe>SubNetwork=NL1_R,SubNetwork=AHPTUR14,MeContext=rbs008841,ManagedElement=1</es:listOfNe>
                            <es:listOfNe>SubNetwork=NL1_R,SubNetwork=AHPTUR14,MeContext=rbs008849,ManagedElement=1</es:listOfNe>
                </xn:VsDataContainer>

output should be in csv format

 rbs008811,site00881
 rbs008819,site00881
 rbs008821,site00882
 rbs008829,site00882
 rbs008831,site00883
 siu008832,site00883
 rbs008841,site00884
 rbs008849,site00884

Upvotes: 0

Views: 712

Answers (2)

glenn jackman
glenn jackman

Reputation: 247162

With the usual reservations about parsing XML:

gawk -v OFS=, '
    match($0, /VsDataContainer id="([^"]+)/, m) {container = m[1]} 
    match($0, /MeContext=([^,]+)/, m)           {print m[1], container}
' file

If you don't have GNU awk:

awk -v OFS=, '
    /VsDataContainer id="/ {
        sub(/.*id="/, "")
        sub(/".*/, "")
        container = $0
    } 
    /MeContext=/ {
        sub(/.*MeContext=/, "")
        sub(/,.*/, "")
        print $0, container
    }
' file

Upvotes: 0

Tiago Lopo
Tiago Lopo

Reputation: 7959

I would help you with xmllint, but your xml file don't seen to be valid.

Anyway here's a quick and dirty solution, which you should probably avoid:

grep -Po "(rbs|site)\d+" file.xml | awk '/site/{site=$1} /rbs/{print $1","site}' 
rbs008811,site00881
rbs008819,site00881
rbs008821,site00882
rbs008829,site00882
rbs008831,site00883
rbs008841,site00884
rbs008849,site00884

Upvotes: 2

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