Reputation: 1726
How do I print out the data type of a macro variable in the log
%macro mymacro(dt2);
%LET c_mth = %SYSFUNC(intnx(month,&dt2.d,-1,e),date9.) ;
%put &c_mth;
%mend;
mymacro('01sep2014')
I have a bunch of macro variables assigned using a %let or into: my problem is I'm trying to do a bunch of boolean condition on dates but I suspect that some of my variables are strings and some are dates I have casted them in my code but to triple check there is surely a way to return something to the log
I want something similar to using str() or mode() or is.numeric() in R
Upvotes: 3
Views: 1240
Reputation: 9569
If your macro variables resolve to date literals, you can use intck
combined with %eval
to compare them, e.g.
%let mvar1 = '01jan2015'd;
%let mvar2 = '01feb2015'd;
/*Prints 1 if mvar2 > mvar1*/
%put %eval(%sysfunc(intck(day,&mvar1,&mvar2)) > 0);
Upvotes: 1
Reputation: 6378
H,
The SAS macro language is weird. : )
As Reeza said, macro variables do not have a type, they are all text.
But, if you use Boolean logic (%IF statement), and both operands are integers, the macro language will do a numeric comparison rather than a character comparison.
So you can use the INPUTN() function to convert the date strings to SAS dates (number of days since 01Jan1960), and then compare those. Here's an example, jumping off from your code:
%macro mymacro(dt1,dt2);
%local c_mth1 c_mth2 n_mth1 n_mth2;
%let c_mth1 = %sysfunc(intnx(month,&dt1.d,-1,e),date9.) ;
%let c_mth2 = %sysfunc(intnx(month,&dt2.d,-1,e),date9.) ;
%let n_mth1 = %sysfunc(inputn(&c_mth1,date9.)) ;
%let n_mth2 = %sysfunc(inputn(&c_mth2,date9.)) ;
%put &c_mth1 -- &n_mth1;
%put &c_mth2 -- &n_mth2;
%if &n_mth1<&n_mth2 %then %put &c_mth1 is before &c_mth2;
%else %put &c_mth1 is NOT before &c_mth2;
%mend;
Log from a sample call:
236 %mymacro('01feb1960','01mar1960')
31JAN1960 -- 30
29FEB1960 -- 59
31JAN1960 is before 29FEB1960
--Q.
Upvotes: 8
Reputation: 21264
Macro variables do not have a type, they are all text.
You have to make sure the variable is passed in a way that makes sense to the program and generates valid SAS code.
%let date1=01Jan2014;
%let date2=31Jan2014;
data _null_;
x = "&date1"d > "&date2"d;
y = "&date2"d > "&date1"d;
z = "&date2"d-"&date1"d;
put 'x=' x;
put 'y=' y;
put 'z=' z;
run;
Log should show: x=0 y=1 z=30
Upvotes: 5