Reputation: 8675
I want to find the index of the nth largest value in an array. I can do the following but it runs into trouble when 2 values are equal.
fltArr(0)=31
fltArr(1)=15
fltArr(2)=31
fltArr(3)=52
For i = 0 To UBound(fltArr)
If fltArr(i) = Application.WorksheetFunction.Large(fltArr, n) Then
result = i
End If
Next
n=1 ---> 3
n=2 ---> 2 (but I want this to be 0)
n=3 ---> 2
n=4 ---> 1
Upvotes: 6
Views: 17189
Reputation: 1234
Here's code for finding the nth largest item in collection. All you need to do is to write a function that would return it's index.
Sub testColl()
Dim tempColl As Collection
Set tempColl = New Collection
tempColl.Add 57
tempColl.Add 10
tempColl.Add 15
tempColl.Add 100
tempColl.Add 8
Debug.Print largestNumber(tempColl, 2) 'prints 57
End Sub
and the function itself, the easiest I could come up with.
Function largestNumber(inputColl As Collection, indexMax As Long)
Dim element As Variant
Dim result As Double
result = 0
Dim i As Long
Dim previousMax As Double
For i = 1 To indexMax
For Each element In inputColl
If i > 1 And element > result And element < previousMax Then
result = element
ElseIf i = 1 And element > result Then
result = element
End If
Next
previousMax = result
result = 0
Next
largestNumber = previousMax
End Function
Upvotes: 0
Reputation: 55682
Uses a second array to quickly get what you want without looping through each element for every value of n
Sub test()
Dim fltArr(0 To 3)
Dim X
Dim n As Long
Dim lngPos As Long
fltArr(0) = 31
fltArr(1) = 15
fltArr(2) = 31
fltArr(3) = 52
X = fltArr
For n = 1 To 4
lngPos = Application.WorksheetFunction.Match(Application.Large(X, n), X, 0) - 1
Debug.Print lngPos
X(lngPos) = Application.Max(X)
Next
End Sub
Upvotes: 6
Reputation: 576
Edit:
Public Sub RunLarge()
Dim n%, i%, result%, count%
Dim fltArr(3) As Integer
Dim iLarge As Integer
fltArr(0) = 31:
fltArr(1) = 15:
fltArr(2) = 31:
fltArr(3) = 52
n = 1
Debug.Print " n", "iLarge", "result"
While n <= 4
count% = n - 1
iLarge = Application.WorksheetFunction.Large(fltArr, n)
For i = 0 To UBound(fltArr)
If fltArr(i) = iLarge Then
result = i
count% = count% - 1
If count% <= 0 Then Exit For
End If
Next
Debug.Print n, iLarge, result
n = n + 1
Wend
End Sub
result:
n iLarge result
1 52 3
2 31 0
3 31 2
4 15 1
Upvotes: 2
Reputation: 6206
Perhaps this:
Public Sub RunLarge()
Dim fltArr() As Variant, X As Long
fltArr = Array(31, 15, 31, 52) 'Create the array
For X = 1 To 4 'Loop the number of large values you want to index
For i = LBound(fltArr) To UBound(fltArr) 'Loop the array
If fltArr(i) = Application.WorksheetFunction.Large(fltArr, 1) Then 'Find first instance of largest value
result = i
fltArr(i) = -9999 'Change the value in the array to -9999
Exit For
End If
Next
Debug.Print result
Next
End Sub
As it finds the first instance of the large number it replaces it with -9999 so on the next sweep it will pick the next instance of it.
Upvotes: 0
Reputation: 577
It's a bit "dirty" but seeing as you're in Excel...
' Create a sheet with codename wsTemp...
For i = 0 To UBound(fltArr)
wsTemp.cells(i,1) = i
wsTemp.cells(i,2) = fltArr(i)
Next
with wsTemp
.range(.cells(1,1),.cells(i,2)).sort(wsTemp.cells(1,2),xlDescending)
end with
Result = wsTemp.cells(n,1)
Then you could also expand the sort to "sort by value then by index" if you wanted to control the "which of two equal 2nds should i choose" thing...
Upvotes: 0