CODEWITHSUNDEEP
javanumberformatexception
user2618021
user2618021

Reputation: 21

NumberFormatException on Double.valueOf with comma decimal separator

Double.valueOf with comma decimal separator throws NumberFormatException. Java 1.7.0_67 and 1.8.0_25.

I also try to set DecimalFormatSymbols with "," as decimalSeparator.

Locale.setDefault(Locale.FRANCE);
assert "12,3".equals(NumberFormat.getInstance().format(12.3));
if (((DecimalFormat) NumberFormat.getInstance()).getDecimalFormatSymbols().getDecimalSeparator() == ',')
    Double.valueOf("12,3");

Upvotes: 2

Views: 3590

Answers (3)

Sireesh Vattikuti
Sireesh Vattikuti

Reputation: 1190

NumberFormat format = NumberFormat.getInstance(Locale.FRANCE);
Number number = format.parse("12,3");
Double d = number.doubleValue();
System.out.println(d);

Upvotes: 3

Adam
Adam

Reputation: 36703

Double.valueOf() is not Locale aware. It only understands numbers with dots as decimal places.

Luckily you can use the same NumberFormat instance for formatting and parsing which is Locale aware ....

NumberFormat format = NumberFormat.getInstance(Locale.FRANCE);

System.out.println(format.format(12.3));   // ==> "12,3"
System.out.println(format.parse("12,3"));  // ==> 12.3

Upvotes: 1

Jesper
Jesper

Reputation: 206816

Double.valueOf(String) does not take the default locale into account. Note that the API documentation of the method explains exactly what format it expects. It also tells you this:

To interpret localized string representations of a floating-point value, use subclasses of NumberFormat.

Use, for example, DecimalFormat instead to parse the string.

DecimalFormat format = new DecimalFormat("##.#");
Double value = (Double) format.parse("12,3");

Upvotes: 0

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