CODEWITHSUNDEEP
swiftdictionary
Bogdan Bogdanov
Bogdan Bogdanov

Reputation: 992

Swift - Arrange Second Dictionary in Dictionary Alphabetically and by values

I have Dictionary of type:Dictionary<String,Dictionary<String,Int64>>

myDict["DictA"]!["ElementB"] = 8
myDict["DictA"]!["ElementC"] = 16
myDict["DictA"]!["ElementA"] = 32

I want to arrange my second dictionary alphabetically:

myDict["DictA"]!["ElementA"] = 32
myDict["DictA"]!["ElementB"] = 8
myDict["DictA"]!["ElementC"] = 16

And by value:

myDict["DictA"]!["ElementA"] = 32
myDict["DictA"]!["ElementC"] = 16
myDict["DictA"]!["ElementB"] = 8

I need func of type arrangeAlphabetically(myDict:Dictionary<String, Int64>)->Dictionary<String, Int64> and another one arrangeByValue.How it will be done?

Upvotes: 1

Views: 73

Answers (2)

rintaro
rintaro

Reputation: 51911

Dictionary is essentially a unordered collection type. Meanwhile, it's a sequence of (Key, Value) pair tuples. You can get sorted() these tuples. 

var myDict:[String:[String:Int64]] = ["DictA":[:]]

myDict["DictA"]!["ElementA"] = 32
myDict["DictA"]!["ElementC"] = 16
myDict["DictA"]!["ElementB"] = 8

let sortedByKeyAsc = sorted(myDict["DictA"]!) { $0.0 < $1.0 } // by keys ascending
let sortedByValDesc = sorted(myDict["DictA"]!) { $0.1 > $1.1 } // by values descending

println(sortedByKeyAsc) // -> [(ElementA, 32), (ElementB, 8), (ElementC, 16)]
println(sortedByValDesc) // -> [(ElementA, 32), (ElementC, 16), (ElementB, 8)]

Upvotes: 0

The Tom
The Tom

Reputation: 2810

Dictionary are by essence unordered so in a few words : you cannot.

You could put your values in arrays in the order you need as array are ordered.

Upvotes: 1

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