Reputation: 422
I am trying to declare a struct and use it in multiple files and I am getting an error that I cannot figure out. Sample code is posted below.
in test.h
#ifndef TEST_H
#define TEST_H
struct mystruct;
struct mystruct *new_mystruct();
void myprint(struct mystruct*,int);
#endif
int test.c
#include "test.h"
#include <stdio.h>
#include <stdlib.h>
struct mystruct {
int *myarray;
};
struct mystruct *new_mystruct(int length)
{
int i;
struct mystruct *s;
s = malloc(sizeof(struct mystruct));
s->myarray = malloc(length*sizeof(int));
for(i = 0; i < length; ++i)
s->myarray = 2*i;
return s;
}
in main.c
#include "test.h"
#include <stdio.h>
int main()
{
int len = 10;
struct mystruct *c = new_mystruct(len);
myprint(c, len);
printf("%f", c->myarray[3]); // error: dereferencing pointer to incomplete type
return 0;
myprint() prints out 0 2 4 6 8 10 12 14 16 18. why doesn't the myprint(function work but the printf statement doesn't? why is it ok to pass it into a function but not use it in main? Thanks.
Upvotes: 0
Views: 1236
Reputation: 53
Main.c doesn't know the contents of the mystruct structure. Try moving these lines:
struct mystruct {
int *myarray;
};
from test.c to test.h.
While you're at it, I think you mean "int myarray" not "int *myarray".
Upvotes: 1
Reputation: 213060
Currently main()
only knows that struct mystruct
is a type, but it doesn't know anything about its internal structure, because you've hidden it in test.c.
So you need to move this definition:
struct mystruct {
int *myarray;
};
from test.c to test.h, so that it's visible to main()
.
Note: what you're doing here is a classic example of an opaque type. This can be a very useful technique when you want to hide implementation details from code that is going to be calling your API.
Upvotes: 1