CODEWITHSUNDEEP
java
Joe
Joe

Reputation: 1498

if block not executing when adding multiple conditions

I am running this program to find even numbers in the array, but i do not want my program to check the index 1 of the array. So I did this,

    int[] numbers = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14 };

    for (int i = 0; i < numbers.length; i++) {
        if ((i != 1)){
            if (numbers[i] % 2 == 0) {
                System.out.print(numbers[i] + " ");
            }
        }
    }

it gives the correct output,

4 6 8 10 12 14

but if i add other condition to skip both index 1 and 3,

i.e, if ((i != 1) || (i != 3) ) then if block is not executed and i get the following output,

2 4 6 8 10 12 14

instead of, 6 8 10 12 14

Why the if block is not executing the multiple conditions ?

Upvotes: 0

Views: 48

Answers (3)

Lev Kuznetsov
Lev Kuznetsov

Reputation: 3728

It is working as it is supposed to as the i variable is either not equal to 1 or not equal to 3 which is true for all numbers. You mean to write i != 1 && i != 3

Upvotes: 0

vikingsteve
vikingsteve

Reputation: 40388

Your condition needs to be if ((i != 1) && (i != 3) )

Upvotes: 2

arshajii
arshajii

Reputation: 129507

if ((i != 1) || (i != 3) )

This is always true.

  • If i is neither 1 nor 3, then both conditions are true.
  • If i is 1, then the right condition is true.
  • If i is 3, then the left condition is true.

Perhaps you want 

if (!(i == 1 || i == 3))

which is equivalent to 

if ((i != 1) && (i != 3))

by De Morgan's Law.

Upvotes: 3

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