CODEWITHSUNDEEP
javaseleniumxpathselenium-webdriverweb-scraping
Zack
Zack

Reputation: 2208

InvalidSelectorError: Compound class names not permitted

I am trying to get each of the below elements using 

element = driver.findElement(By.className("code-list-item code-list-item-public "));

The output of inspect element is as follows.

<div class="column one-fourth codesearch-aside"></div>

<div class="column three-fourths codesearch-results">

    <div class="sort-bar"></div>
    <div id="code_search_results">
        <div class="code-list">
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
            <div class="code-list-item code-list-item-public "></div>
        </div>

But it fails and throws the below error. 

Caused by: org.openqa.selenium.InvalidSelectorException: The given selector code-list-item code-list-item-public  is either invalid or does not result in a WebElement. The following error occurred:
InvalidSelectorError: Compound class names not permitted
For documentation on this error, please visit: http://seleniumhq.org/exceptions/invalid_selector_exception.html

Also, How do I traverse through each of the classes? Each of these contain subparts which I would like to process further individually before moving to the next.

enter image description here

enter image description here

Upvotes: 2

Views: 14680

Answers (1)

Saifur
Saifur

Reputation: 16201

I wouldn't worry about the class name that much if I don't have to. I would use css selector.

.code-list>div

Notice in css . means class so I am pointing to the div with the class code-list and >div it allows us to select all child div

You also can use :nth-child() function to grab a specific child div with index number

.code-list>div:nth-child(1)

The above css allows you to select the first child div

As per your screenshot

.code-list>div:nth-child(1)>a

A code block that may help OP to understand how this scenario should be handled

//maximizing the window for better view
driver.manage().window().maximize();

//a selector to find all the links on the page
By selector = By.xpath("//p[@class='title']/a[1]");

//finding the list of all elements
List<WebElement> list = driver.findElements(selector);

/*Iterating over the collection may throw StaleElementReference exception due to DOM refresh
according to my knowledge for loop is best in such case
*/
for (int i = 0; i<list.size(); i++){

    new WebDriverWait(driver,10).until(ExpectedConditions.elementToBeClickable(selector));

    //Click on the title
    driver.findElements(selector).get(i).click();

    //Navigating back to the main page. This is not feasible but no other option present due to page structure
    driver.navigate().back();
}

Upvotes: 2

Related Questions