Reputation: 158
I seem to have an issue with my matrix multiplication function.
When I run the program I just get an n x n matrix with all of the values the same, as some wired double value, e.g 21312e-2 Here is my function code:
void Multiply(int i, int j, double mat1[10][10], double mat2[10][10]) {
double mat3[10][10];
for (int r = 0; r < i; r++) {
for (int c = 0; c < j; c++) {
for (int in = 0; in < i; in++) {
mat3[r][c] += mat1[r][in] * mat2[in][c];
}
cout << mat3[r][c] << " ";
}
cout << "\n";
}
}
mat1 and mat 2 are read into the program in the main thread using the function read:
void read_matrix(int m, int n, double mat[10][10])
{
int i, j;
for (i = 0; i<m; ++i)
for (j = 0; j<n; ++j)
cin >> mat[i][j];
}
Edit:Main Code
int main()
{
int i1, i2, j1, j2;
double mat1[10][10], mat2[10][10], mat3[10][10];
scanf_s("%d %d\n", &i1, &j1, mat1);
read_matrix(i1, j1, mat1);
scanf_s("%d %d\n", &i2, &j2, mat2);
read_matrix(i2, j2, mat2);
printf("%d x %d matrix\n", i1, j1);
print_matrix(i1, j1, mat1);
printf("\n%d x %d matrix\n", i2, j2);
print_matrix(i2, j2, mat2);
Multiply(i1, j2, mat1, mat2);
system("pause");
return 0;
}
Upvotes: 1
Views: 9359
Reputation: 129314
You need to fill mat3
with a zero value before adding to it.
Simplest way is to use:
double mat3[10][10] = {};
Upvotes: 4