Th3carpenter
Th3carpenter

Reputation: 201

Add 2 numbers and print the result using Assembly x86

I'm a novice Assembly x86 Learner, and i want to add two numbers (5+5) and print the result on the screen.

here is my code:

global _start

section .text
_start:
    mov eax, 5
    mov ebx, 5
    add eax, ebx
    push eax
    mov eax, 4 ; call the write syscall
    mov ebx, 1 ; STDOUT
    pop ecx    ; Result
    mov edx, 0x1
    int 0x80

    ; Exit
    mov eax, 0x1
    xor ebx, ebx
    int 0x80

It exits without printing anything.

Upvotes: 0

Views: 15148

Answers (1)

rkhb
rkhb

Reputation: 14399

You're popping the value 10 into ECX, and passing that to a write system call as the address. It's not a valid address so it returns -EFAULT; use strace ./a.out to see that. write(int fd_ebx, void *buf_ecx, size_t len_edx).

You could mov ecx, esp to pass the address of the bytes you pushed, but that's an integer 10 (ASCII newline). You need to pass a pointer to ASCII digit characters that represent your number, like what printf does.

One approach to convert an unsigned integer to a string and write it, using a buffer on the stack:

section .text
global _start
_start:

    mov eax, 1234567890
    mov ebx, 5
    add eax, ebx

    ; Convert EAX to ASCII and store it onto the stack
    sub esp, 16             ; reserve space on the stack
    mov ecx, 10
    mov ebx, 16
    .L1:
    xor edx, edx            ; Don't forget it!
    div ecx                 ; Extract the last decimal digit
    or dl, 0x30             ; Convert remainder to ASCII
    sub ebx, 1
    mov [esp+ebx], dl       ; Store remainder on the stack (reverse order)
    test eax, eax           ; Until there is nothing left to divide
    jnz .L1

    mov eax, 4              ; SYS_WRITE
    lea ecx, [esp+ebx]      ; Pointer to the first ASCII digit
    mov edx, 16
    sub edx, ebx            ; Count of digits
    mov ebx, 1              ; STDOUT
    int 0x80                ; Call 32-bit Linux

    add esp, 16             ; Restore the stack

    mov eax, 1              ; SYS_EXIT
    xor ebx, ebx            ; Return value
    int 0x80                ; Call 32-bit Linux

See also How do I print an integer in Assembly Level Programming without printf from the c library? (itoa, integer to decimal ASCII string) for more background on the algorithm of repeated division by 10, an x86-64 assembly version, and ways to do it more efficiently.

Upvotes: 4

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