CODEWITHSUNDEEP
javascriptjqueryhtml
user4552957
user4552957

Reputation:

Why won't this jquery work?

I want it so that when a person presses the enter button, it would execute my function.

Here is the code:

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js">
    $('textmoney').keydown(function (e){
    if(e.keyCode == 13){
        moneyFunction();
    }
})
    </script>

Why won't this work?

Upvotes: 0

Views: 40

Answers (3)

Karl-Andr&#233; Gagnon
Karl-Andr&#233; Gagnon

Reputation: 33870

As others stated, you are missing a ID or class selector before textmoney. It should be #textmoney or .textmoney.

But you are also inserting your script inside the script tag loading jQuery. You can't do that. It is either you load a source or you run the code between the tag. The src is always prioritized so your code will never be run.

Separate the two, use 2 script tags :

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
    $('#textmoney').keydown(function (e){
        if(e.keyCode == 13){
            moneyFunction();
        }
    });
</script>

Upvotes: 0

Hazem Hagrass
Hazem Hagrass

Reputation: 9808

I think you are missing either id or class in jQuery selector, so it should be like $('#textmoney') or $('.textmoney')depending on your selector.

Upvotes: 0

Milind Anantwar
Milind Anantwar

Reputation: 82231

You are missing either ID or class selector while attaching the event.

If textmoney is class

$('.textmoney').keydown(function (e){
 if(e.keyCode == 13){
    moneyFunction();
}});

If textmoney is ID

$('#textmoney').keydown(function (e){
 if(e.keyCode == 13){
   moneyFunction();
}});

Upvotes: 3

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