CODEWITHSUNDEEP
lualua-patternsasa
Kevin Pease
Kevin Pease

Reputation: 31

Lua script - find digits in a string

I have a Cisco ASA 8.4 VPN Concentrator. I am trying to use Lua to extract digits from a certificate string coming in and use them in a LDAP lookup with AD for authorization. I found a string that works...sometimes.

The string comes in with the format: 

LAST_NAME.FIRST_NAME.MIDDLE_NAME.1234567890

My LDAP only wants to see the digits and @domainname. The script I am currently us is: return string.gsub(cert.subject.cn, "^(%w+)%.(%w+)%.(%w+)%.(%w+)$", "%4@domain")

This script works fine in most cases (80-90% of the time). When it doesn't work is when people have no middle name, 4 names instead of 3, etc.

My question is how can I get it to output only the 10 digits, regardless of what comes before it. Seems too easy with a return string.match, but so far I can't get it to work. Any ideas?

Upvotes: 3

Views: 1402

Answers (1)

Yu Hao
Yu Hao

Reputation: 122493

You can use the pattern .*(%d%d%d%d%d%d%d%d%d%d)$:

local str = 'LAST_NAME.FIRST_NAME.MIDDLE_NAME.1234567890'
print(str:match('.*(' .. ('%d'):rep(10) .. ')$'))

or .*(%d+)$ if the number of digits is always 10.

If the 10 digits is always the last 10 characters, this works:

print(str:sub(-10, -1))

Upvotes: 4

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