Reputation: 1851
I have a char array:
char tmp[2048];
I want to cut of the first x words of tmp. I define a word as a sequence of characters that does not include whitespaces. I tried something like this (should cut of the first 3 words):
sscanf(tmp, "%*s %*s %*s %s", tmp);
My problem is, that '%s' stops at the first whitespace it finds. I want the new string to end at the end of the old string, not at the first whitespace.
I'm also open for other suggestions how to cut of the first x words of a string. I define a word as a sequence of characters that doesn't contain whitespaces.
Upvotes: 0
Views: 124
Reputation: 1736
You can use strtok
to tokenize strings by whitespace. Something similar to this could do what you're trying to achieve:
#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[])
{
// Number of words to trim
const int numWords = 2;
char tmp[1024];
char buffer[1024];
sprintf(tmp, "this is a\tsentence.");
strcpy(buffer, tmp);
char* token = strtok(buffer, " \t");
for (int i = 0; i < numWords && token; i++) {
token = strtok(NULL, " \t");
}
if (token) {
size_t len = 1024 - (token - buffer);
memmove(tmp, tmp + (token - buffer), len);
}
else {
memset(tmp, '\0', 1024);
}
// Prints "a sentence."
printf("%s", tmp);
return 0;
}
However, the use of strtok
is tricky at best. I would suggest using an approach similar to that of abelenky's answer.
Upvotes: 0
Reputation: 64730
Here's a rough implementation:
const char* TrimWords(const char* input, int nWords)
{
while (nWords)
{
if (!isspace(*input) && isspace(*(input + 1)))
{
nWords--;
}
input++;
}
return input;
}
TrimWords("One Two Three Four Five", 3);
// returns " Four Five" after the first 3 words are trimmed.
Detailed input validation and error checking is left to the OP.
This is just a good starting point.
Upvotes: 1
Reputation: 528
use strncpy(tmp, n, tmp+m);
where m and n are ints
char tmp[20] = "abcdef";
strncpy(tmp, tmp + 3, 2);
for exmaple: code above will result in decdef
Upvotes: 0