CODEWITHSUNDEEP
regexawk
Hallucigeniak
Hallucigeniak

Reputation: 155

AWK use value of field in regex

I'm trying to find a string pattern composed of the word CONCLUSION followed by the value of field $2 and field $3 from the same record in field $5.

For example, my_file.txt is separated by "|":

1|substance1|substance2|red|CONCLUSIONS: the effect of SUBSTANCE1 and SUBSTANCE2 in humans...|
2|substance3|substance4|red|Conclusions: Substance4 is not harmful...|
3|substance5|substance6|red|Substance5 interacts with substance6...|

So in this example I only want the first record to be printed because it has the word "CONCLUSIONS" followed by substance1 followed by substance2.

This is what I'm trying but it's not working:

awk 'BEGIN{FS="|";IGNORECASE=1}{if ($5 ~ /CONCLUSIONS.*$2.*$3/) {print $0}}' my_file.txt

Any help is much appreciated

Upvotes: 5

Views: 384

Answers (1)

John1024
John1024

Reputation: 113994

$ awk 'BEGIN{FS="|";IGNORECASE=1} $5 ~ "conclusions.*" $2 ".*" $3' my_file.txt
1|substance1|substance2|red|CONCLUSIONS: the effect of SUBSTANCE1 and SUBSTANCE2 in humans...|

How It Works

  • BEGIN{FS="|";IGNORECASE=1}

    This part is unchanged from the code in the question.

  • $5 ~ "conclusions.*" $2 ".*" $3

    This is a condition: it is true if $5 matches a regex composed of four strings concatenated together: "conclusions.*", and $2, and ".*", and $3.

    We have specified no action for this condition. Consequently, if the condition is true, awk performs the default action which is to print the line.

Simpler Examples

Consider:

$ echo "aa aa" | awk '$2 ~ /$1/'

This line prints nothing because awk does not substitute in for variables inside a regex.

Observe that no match is found here either:

$ echo '$1' | awk '$0 ~ /$1/'

There is no match here because, inside a regex,$ matches only at the end of a line. So, /$1/ would only match the end of a line followed by a 1. If we want to get a match here, we need to escape the dollar sign:

$ echo '$1' | awk '$0 ~ /\$1/'
$1

To get a regex that uses awk variables, we can, as is the basis for this answer, do the following:

$ echo "aa aa" | awk '$2 ~ $1'
aa aa

This does successfully yield a match.

A Further Improvement

As Ed Morton suggests in the comments, it might be important to insist that the substances match only on whole words. In that case, we can use \\<...\\> to limit substance matches to whole words. Thus:

awk 'BEGIN{FS="|";IGNORECASE=1} $5 ~ "conclusions.*\\<" $2 "\\>.*\\<" $3 "\\>"' my_file.txt

In this way, substance1 will not match substance10.

Upvotes: 5

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