CODEWITHSUNDEEP
maven
Jerome Serrano
Jerome Serrano

Reputation: 1855

How to get the classifier name from Maven's properties?

What's the easiest way to get the classifier name from Maven's properties and use it as a variable in the pom.xml?

For example:

<properties>
   <final_jar>${project.build.finalName}-${classifier}.jar</final_jar>
</properties>

There is no mention of a classifier property in the official documentation.

Looking at the source of maven-jar-plugin, it seems that it's getting it from a property called maven.jar.classifier but it doesn't seem to be available outside the plugin. Is there any way to access it ?

Upvotes: 7

Views: 1706

Answers (1)

Gerold Broser
Gerold Broser

Reputation: 14772

Despite of classifier being mentioned under POM Reference, Maven Coordinates it has to be declared in a maven-jar-plugin section. So (you name it) it's not part of the <project> element's Model.

Unfortunately, I too haven't found a way yet to access the maven.jar.classifier property of the maven-jar-plugin but by declaring an extra <project> property:

<project>
  ...
  <properties>
    <jar.classifier>CLASSIFIER</jar.classifier>
  </properties>
  ...
      <plugin>
        <groupId>org.apache.maven.plugins</groupId>
        <artifactId>maven-jar-plugin</artifactId>
        <version>2.6</version>
        <configuration>
          <classifier>${jar.classifier}</classifier>
        </configuration>
      </plugin>
  ...
</project>

There's a Properties properties in the Maven Model's superclass ModelBase. But if it's not used by a plugin...

And there's also no property interpolation syntax (yet?) like:

${project.build.plugins.plugin[<G>:<A>:<V>].<property>}

Upvotes: 1

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