Reputation: 623
Trying to continue with my assignment but would like to sidetrack and figure out how array of structs work. Not sure if I'm not looking hard enough but I can't seem to find an answer.
Let's say I have one source file, main.c
#include "data.h" //this contains the struct data.
newPerson person[20];
int mainMenu(){
addName();
}
void addName(){
strcpy(person[0].firstName, "George");
}
Doing it this way, I'm able to access the array of struct, however isn't this method considered taboo since my array of person is a global variable?
I then tried moving the array initialization into the main function instead
#include "data.h" //this contains the struct data.
int mainMenu(){
newPerson person[20];
addName();
}
void addName(){
strcpy(person[0].firstName, "George");
}
Doing it this way, when I get to the addName() function, I get a 'person undeclared' error. How can I access the person[] array outside of its function without making it a global variable? Thank for the help in advance. Below I have the example data.h included if needed.
data.h
typedef struct person{
char firstName[20];
char familyName[20];
char telephoneNum[20];
}newPerson;
Upvotes: 0
Views: 56
Reputation: 7
Yeah, pass the variable, person in this case.
person is an array of struct newPerson.
to pass arrays as parameters you should define the function like this
//Option 1, the last dimension without number
void addName(newPerson person[]){
//...
}
//Option 2, as a pointer, but it neets a cast on the call (newPerson*)
void addName(newPerson *person){ //I prefer option 1
//...
}
Upvotes: 0
Reputation: 53036
Just pass parameters to the addName()
function.
Example
#include "data.h" //this contains the struct data.
int mainMenu(){
newPerson person[20];
addName(person, 0, "George");
}
void addName(newPerson *person, unsigned int index, const char *const name) {
if ((person == NULL) || (index >= 20))
return; /* ^ this number could be specified with a macro */
/* or via a parameter */
strcpy(person[index].firstName, name);
}
Upvotes: 2