Reputation: 51
I am having a hard time understanding how to convert amounts such as $1.17 into this output:
I need to use if statements which I can figure out but, the problem i am having is trying to get the change amounts to display correctly. Here is my code. I`m a visual learner so if you start me in the right direction that would be helpful.
import java.util.Scanner;
public class ComputeChange {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter an amount in double, for example 11.56: " );
double number = input.nextDouble();
System.out.println("Your amount " + number + " consists of ");
int Dollars = (int) (number);
int Quarters = Dollars / 25;
if (number == 1) {
System.out.print("1 dollar ");
}
else if (number > 1) {
System.out.print((int)Dollars + " dollars ");
}
if (number == 0) {
System.out.println("");
}
System.out.print( Quarters + " Quarters ");
}
}
Upvotes: 1
Views: 81
Reputation: 51711
A much simpler approach than using modulus is to calculate the units of measurement in top-down fashion (from the highest to the lowest) and keep deducting them from the total already converted into the lowest unit.
A lot of libraries use this approach with units of time as well i.e. converting a time span into hours, minutes and seconds. Here's the same approach for currency. I've added inline comments to explain the code as best as possible.
// Scan the amount
Scanner scanner = new Scanner(System.in);
System.out.print("Enter amount: ");
double amount = scanner.nextDouble();
scanner.close();
// convert into cents
int cents = (int) (amount * 100);
// get dollars
int dollars = cents/100;
// cents left after dollars
cents = cents - dollars*100;
// get quarters
int quaters = cents/25;
// cents left after quarters
cents = cents - quaters*25;
// get dimes
int dimes = cents/10;
// cents left after dimes
cents = cents - dimes*10;
// get nickels
int nickels = cents/5;
// cents left after nickels
cents = cents - nickels*5;
// leftover cents are pennies
int pennies = cents;
Now, just build the output message with a StringBuilder
as
StringBuilder msg = new StringBuilder("You have:");
if (dollars > 0) {
msg.append(" ").append(dollars).append(" dollar").append(dollars > 1 ? "s" : "");
}
if (quaters > 0) {
msg.append(" ").append(quaters).append(" quarter").append(quaters > 1 ? "s" : "");
}
if (dimes > 0) {
msg.append(" ").append(dimes).append(" dime").append(dimes > 1 ? "s" : "");
}
if (nickels > 0) {
msg.append(" ").append(nickels).append(" nickel").append(nickels > 1 ? "s" : "");
}
if (pennies > 0) {
msg.append(" ").append(pennies).append(" pennie").append(pennies > 1 ? "s" : "");
}
System.out.println(msg);
Output :
Enter amount: 1.17
You have: 1 dollar 1 dime 1 nickel 2 pennies
Enter amount: 12.99
You have: 12 dollars 3 quarters 2 dimes 4 pennies
Upvotes: 1
Reputation: 11440
You will probably want to use the modulus operator %
. It is used with 2 numbers and returns the remainder of a
divided by b
where a
is the left hand assignment and b
is the right hand represented like a%b
.
Example:
11%2=1
explanation: 5*2 = 10
, 11-10 = 1
.66%.25=.16
explanation: 2*.25 = .5
, .66-.5=.16
Start with a simple problem where you only have 2 types of coins, say 8¢
or $0.08
.
double monies = .08;
int numNickles = (int)(monies/.05) = 1 // one nickle
monies = monies % .05; // or you can write as monies %=.05;
// monies value should now be .03
int numPennies = (int)(monies/.01) = 3 // three pennies
Upvotes: 2