CODEWITHSUNDEEP
probabilitybayesian-networks
NoviceHacker
NoviceHacker

Reputation: 13

Bayesian Probability

I have probability P(A|B=T,C=F,D=F,G=T) is this same as computing P(A|B=T)*P(A|C=F)*P(A|D=F) *P(A|G=T) ? P(A|B=T,C=F,D=F,G=T)=P(A|B=T)*P(A|C=F)*P(A|D=F) *P(A|G=T) ? where A is the child of B, C, D, G thanks!

Upvotes: 0

Views: 226

Answers (1)

Timothy Shields
Timothy Shields

Reputation: 79581

In general it is not true that the following holds.

P(A|B,C) = P(A|B) • P(A|C)

The following is true, however. (Bayes' theorem)

           P(B,C|A) • P(A)
P(A|B,C) = ━━━━━━━━
                P(B,C)

Furthermore, if B and C are conditionally independent given A, the following is true.

P(A|B,C) ∝ P(B|A) • P(C|A) • P(A)

Upvotes: 1

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