Reputation: 991
I'm curious why this one
<div class = "overlay">
fdsfsd
</div>
.overlay{
width: 100px;
height: 200px;
background-color:red;
}
alert(document.getElementsByClassName("overlay")[0].style.width);
is not alerting nothing. Of course I can write <div style = "width:100px">
then everthing works fine, but it is not good for me, I need css.
Here you can find a jsfiddle demo
So exact question is: why this code is not alerting width of div and how alert it if width is given by css?
Upvotes: 8
Views: 877
Reputation: 7026
The style gives access only to information which is put into elem.style
. In your example style doesn’t tell anything about the margin defined in CSS. Use getComputedStyle().
var computedStyle = getComputedStyle(document.getElementsByClassName("overlay")[0], null)
alert(computedStyle.width);
Upvotes: 1
Reputation: 253308
As noted elsewhere, the problem is that HTMLElement.style
retrieves the values from the style
attribute of the element; as you're setting your style with CSS, you need to instead use window.getComputedStyle(element, null).width
:
var elem = document.getElementsByClassName("overlay")[0],
width = window.getComputedStyle(elem, null).width;
console.log(width);
.overlay {
width: 100px;
height: 200px;
background-color: red;
}
<div class="overlay">
fdsfsd
</div>
References:
Upvotes: 10
Reputation: 2938
The .style is inline style="width:100px;"
only...
If it's in CSS (rather than inline) you need getComputedStyle -
https://developer.mozilla.org/en/docs/Web/API/window.getComputedStyle
Upvotes: 0
Reputation: 7301
The JavaScript .style
only relates to inline styles on the element.
See Documentation.
If you want to get the width of an element you should use offsetWidth
.
document.getElementsByClassName("overlay")[0].offsetWidth
http://jsfiddle.net/9kwap3zy/7/
Upvotes: 5