CODEWITHSUNDEEP
javascriptphpjqueryajaxpost
HakoStan
HakoStan

Reputation: 69

Can't send file with ajax to php file

I am having a problem with receiving File Data.

This is my HTML FORM:

<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> 
<title>Upload</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.0/jquery.min.js"></script>
<script type="text/javascript" src="General.js"></script>
</head>

<body>
<form method="post" enctype="multipart/form-data" id="Form" action="upload.php">
<table width="350" border="0" cellpadding="1" cellspacing="1" class="box">
<tr> 
<td width="246">
<input type="hidden" name="MAX_FILE_SIZE" value="2000000">
<input name="userfile" type="file" id="userfile"> 
</td>
<td width="80"><input name="submit" type="submit" class="box" id="submit" value=" Upload "></td>
</tr>
</table>
</form>

As you can see it sends us to the file General.js

$(document).ready(function (e){
$("#Form").on('submit',(function(e){
	e.preventDefault();
	var formData = new FormData(document.getElementById('userfile'));
	// AJAX Code To Submit Form.
	$.ajax({
		type: "POST",
		url: "uploader.php",
		data: formData,
		cache: false,
		contentType: false,
		processData: false,
		success: function(callback){
		alert(callback);
	}
	});

	return false;
})
);
});

and the php page that need to recieve this:

$fileName = $_FILES['userfile']['name'];
$tmpName  = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];

Everything works fine, but the problem is when i send the data to the php file, it doesn't receive it as it should. Maybe i need to use some addition things? Because the name of the file and the size and everything is empty.

EDIT:

$(document).ready(function(){
$("#submit").click(function(){
var formData = new FormData($('form')[0]);
// AJAX Code To Submit Form.
$.ajax({
type: "POST",
url: "uploader.php",
xhr: function() {  // Custom XMLHttpRequest
            var myXhr = $.ajaxSettings.xhr();
            if(myXhr.upload){ // Check if upload property exists
                myXhr.upload.addEventListener('progress',progressHandlingFunction, false); // For handling the progress of the upload
            }
            return myXhr;
			},
data: formData,
cache: false,
contentType: false,
processData: false,
success: function(callback){
alert(callback);
}
});

return false;
});
});

function progressHandlingFunction(e){
    if(e.lengthComputable){
        $('progress').attr({value:e.loaded,max:e.total});
    }
}

Also tried this code, but still it doesn't send the right information to the page. I am getting on the uploader.php page an error that says that the name of the file is empty, what means that maybe i don't receive it good or it didn't send at all.

Upvotes: 2

Views: 4020

Answers (2)

Vishal Wadhawan
Vishal Wadhawan

Reputation: 1085

change 

    var formData = new FormData(document.getElementById('Form'));

to

   var fd = new FormData();     
   fd.append("userfile", document.getElementById('userfile').value);

Upvotes: 0

Moid
Moid

Reputation: 1447

Try using this...

    $(document).ready(function (e) {
    $("#Form").on('submit',(function(e) {
        e.preventDefault();
        $.ajax({
            url: "uploader.php", // Url to which the request is send
            type: "POST",             // Type of request to be send, called as method
            data: new FormData(this), // Data sent to server, a set of key/value pairs (i.e. form fields and values)
            contentType: false,       // The content type used when sending data to the server.
            cache: false,             // To unable request pages to be cached
            processData:false,        // To send DOMDocument or non processed data file it is set to false
            success: function(data)   // A function to be called if request succeeds
            {
                 console.log(data);
            }
        });
    }));
});

Upvotes: 4

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