CODEWITHSUNDEEP
java
Scurie DS
Scurie DS

Reputation: 13

Try and catch problems

I am trying to write a ' try and catch ' method in this example, but for some reason I'm getting in error on all of my variables saying; "cannot find symbol". This is happening in all instances of: subtotal & customerType. Does anyone know what can be causing this?

import java.text.NumberFormat;
import java.util.Scanner;
import java.util.*;

public class InvoiceApp
{
public static void main(String[] args)
{
    Scanner sc = new Scanner(System.in);
    String choice = "y";

    while (!choice.equalsIgnoreCase("n"))
    {
        // get the input from the user
        try
        {    
        //System.out.print("Enter customer type (r/c): ");
            String customerType = getValidCustomerType(sc);
            System.out.print("Enter subtotal:   ");
            double subtotal = sc.nextDouble();
        }
        catch (InputMismatchException e)
        {
            sc.next();
            System.out.println("Error! Invalid number. Try again \n");
            continue;
        }

        // get the discount percent
        double discountPercent = 0;
        if (customerType.equalsIgnoreCase("R"))
        {
            if (subtotal < 100)
                discountPercent = 0;
            else if (subtotal >= 100 && subtotal < 250)
                discountPercent = .1;
            else if (subtotal >= 250)
                discountPercent = .2;
        }
        else if (customerType.equalsIgnoreCase("C"))
        {
            if (subtotal < 250)
                discountPercent = .2;
            else
                discountPercent = .3;
        }
        else
        {
            discountPercent = .1;
        }

        // calculate the discount amount and total
        double discountAmount = subtotal * discountPercent;
        double total = subtotal - discountAmount;

        // format and display the results
        NumberFormat currency = NumberFormat.getCurrencyInstance();
        NumberFormat percent = NumberFormat.getPercentInstance();
        System.out.println(
                "Discount percent: " + percent.format(discountPercent) + "\n" +
                "Discount amount:  " + currency.format(discountAmount) + "\n" +
                "Total:            " + currency.format(total) + "\n");

        // see if the user wants to continue
        System.out.print("Continue? (y/n): ");
        choice = sc.next();
        System.out.println();
    }
}

Upvotes: 1

Views: 158

Answers (4)

Scurie DS
Scurie DS

Reputation: 13

    private static String getValidCustomerType(Scanner sc)
{
    String customerType = "";
    boolean isValid = false;
    while (isValid == false)
    {
        System.out.print("Enter customer type (r/c): ");
        customerType = sc.next();
        if  (customerType.equalsIgnoreCase("r") || (customerType.equalsIgnoreCase("c")))
        isValid = true;            
       else
        {
            System.out.println("Invalid customer type. Try again. \n");
        }    
        sc.nextLine();
    }
    return customerType;
}
}

Upvotes: 0

z242
z242

Reputation: 435

You declared subtotal and customertype inside the brackets of the try {}. That is the only place where they are valid. If you declared them before the try this would have been fine.

Upvotes: 0

Sergey Kalinichenko
Sergey Kalinichenko

Reputation: 726479

The problem with your code is the scope of your variables: if you declare something in a try block, it is visible only within that try block; it is not going to be visible outside the try block, including even the catch blocks after it.

In order to get around this problem, declare the variable outside the try block:

String customerType;
double subtotal;
try {    
//System.out.print("Enter customer type (r/c): ");
    customerType = getValidCustomerType(sc);
    System.out.print("Enter subtotal:   ");
    subtotal = sc.nextDouble();
} catch (InputMismatchException e) {
    sc.next();
    System.out.println("Error! Invalid number. Try again \n");
    continue;
}

Upvotes: 1

Iswanto San
Iswanto San

Reputation: 18569

You declare subtotal and customerType in try block, so that variable only visible in try block.

Change your code like this will fix the problem:

double subtotal = 0;
String customerType = "";
try
{    
        //System.out.print("Enter customer type (r/c): ");
        String customerType = getValidCustomerType(sc);
        System.out.print("Enter subtotal:   ");
        subtotal = sc.nextDouble();
}
catch (InputMismatchException e)
{
        sc.next();
        System.out.println("Error! Invalid number. Try again \n");
        continue;
}

More : Blocks and Statements

Upvotes: 1

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