Reputation: 726
I will explain how to reproduce my problem:
Log into my page: session variables are set as $_SESSION['logged'] = true
and $_SESSION['id'] = 123
.
Inside the main menu, click the log out option. The code is like this:
function logout()
{
session_start();
$_SESSION['id'] = null;
$_SESSION['logged'] = null;
unset($_SESSION);
session_destroy();
require_once('Views/SessionExpiredView.php');
}
In the session expired view I display a link to the login page; there, the session is null.
I click back on the browser, and click OK to resend information.
The session becomes again $_SESSION['logged'] = true
and $_SESSION['id'] = 123
and I am logged in again and able to see all the information related to the ID 123.
This is a security issue and I don't know what is happening.
Upvotes: 3
Views: 817
Reputation: 86
Step 4: You click back and click “Resend information” — that means that you have resent your previous POST information (apparently the login and the password) — so nothing unusual.
A hint: just make a redirect after logging the user in.
Upvotes: 3
Reputation: 91734
Your step 4. is the problem, you click ok to resend the information, which is effectively your login information from step 1.
You are just logging in again...
Upvotes: 0