CODEWITHSUNDEEP
pythondjangopost
Omega Doe
Omega Doe

Reputation: 345

python script to handle uploaded file via http post

I am working on a django project where i try to upload a file via http post request.

my upload script is : 

url=r'http://MYSITEURL:8000/upload'
files={'file':open('1.png','rb')}
r=requests.post(url,files=files)

my receiving side is in my django site , in views.py:

def upload_image(request):
from py_utils import open_py_shell;open_py_shell.open_py_shell()

when i do request.FILES i can see all the post details, what i want to know is how to save it in the server side once i got the post request

Upvotes: 0

Views: 445

Answers (2)

Noyan
Noyan

Reputation: 44

I think you can work with models well. It will be the right way for Django. Here is an example, models.py file:

from django.db import models
from django.conf import settings

import os
import hashlib


def instanced_file(instance, filename):
    splitted_name = filename.split('.')
    extension = splitted_name[-1]
    return os.path.join('files', hashlib.md5(str(instance.id).encode('UTF-8')).hexdigest() + '.' + extension)

class File(models.Model):
    name = models.FileField('File', upload_to = instanced_file)

    def get_file_url(self):
        return '%s%s' % (settings.MEDIA_URL, self.name)

    def __str__(self):
        return self.name

    def __unicode__(self):
        return self.name

After the creating models create forms and go on.

Upvotes: 0

Dariusz Aniszewski
Dariusz Aniszewski

Reputation: 457

What you have in request.FILES is InMemoryUploadedFile. You just need to save it somewhere in file system.

This is example method taken from Django docs:

def handle_uploaded_file(f):
    with open('some/file/name.txt', 'wb+') as destination:
        for chunk in f.chunks():
            destination.write(chunk)

Upvotes: 1

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