Reputation: 291
I wrote this function which merges two lists together but as I'm fairly new to functional programming I was wondering whether there is a better (simpler) way to do it?
let a = ["a"; "b"; "c"]
let b = ["d"; "b"; "a"]
let merge a b =
// take all a and add b
List.fold (fun acc elem ->
let alreadyContains = acc |> List.exists (fun item -> item = elem)
if alreadyContains = true then
acc
else
elem :: acc |> List.rev
) b a
let test = merge a b
Expected result is: ["a"; "b"; "c"; "d"], I'm reverting the list in order to keep the original order. I thought I would be able to achieve the same using List.foldBack (and dropping List.rev) but it results in an error:
Type mismatch. Expecting a
'a
but given a
'a list
The resulting type would be infinite when unifying ''a' and ''a list'
Why is there a difference when using foldBack?
Upvotes: 2
Views: 8568
Reputation: 243041
If I wanted to write this in a way that is similar to your original version (using fold
), then the main change I would do is to move List.rev
outside of the function (you are calling List.rev
every time you add a new element, which is wrong if you're adding even number of elements!)
So, a solution very similar to yours would be:
let merge a b =
(b, a)
||> List.fold (fun acc elem ->
let alreadyContains = acc |> List.exists (fun item -> item = elem)
if alreadyContains = true then acc
else elem :: acc)
|> List.rev
This uses the double-pipe operator ||>
to pass two parameters to the fold
function (this is not necessary, but I find it a bit nicer) and then passes the result to List.rev
.
Upvotes: 4
Reputation: 65421
You could use something like the following
let merge a b =
a @ b
|> Seq.distinct
|> List.ofSeq
Note that this will preserve order and remove any duplicates.
In F# 4.0 this will be simplified to
let merge a b = a @ b |> List.distinct
Upvotes: 9