CODEWITHSUNDEEP
linuxbashshellscripting
picolin4444
picolin4444

Reputation: 11

Escape special characters in a bash script

I have a command that I want to put in a script but I'm having issues. The command is very picky and it looks like this:

command_to_run -H 'ip_address' -u 'user' -p 'passwd' --register naming_data "/location/of/backup/folder/" "[destination-location]"

I want to create an interactive bash script that asks the user for the ip_address, user, password, location of backup folder and a destination location. The problem I'm having is that I'm storing the user's input on variables (IP_ADD, USERNAME, etc) but when I pass it to the command like

$COMMAND -H '$IPADD' -u '$USERNAME' .....

but again my issues are in the single quotes, the "/" the "[]" ad passing the variables. Can anyone give me a hint and what I need to fix in order to have it working??

Upvotes: 0

Views: 150

Answers (2)

candymanuu
candymanuu

Reputation: 110

Like Etan said, use double quotes:

command_to_run -H "$ip_address" -u "$user" -p "$passwd" ....

Upvotes: 1

hek2mgl
hek2mgl

Reputation: 157947

Use double quotes:

$COMMAND -H "$IPADD" -u "$USERNAME" ...

If you use single quotes in the shell, variables will not getting expanded meaning the literal $USERNAME will being used for the username.

Upvotes: 0

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