Reputation: 1421
I have an ArrayList
with several objects per index. I want to sort this list alphanumerically by one object in particular. The object is "my_id" and the values for this object can look similar to: 1A, 10B, 11B, 2C, 205Z, etc.
I need to sort these to come out: 1A, 2C, 10B, 11B, 205Z. Where the numeric part is sorted first, then the alpha- part is sorted secondary. 1,2,3,4,5,... A,B,C,D,E,...
I checked out some alphanumeric string sorting that worked really well: http://sanjaal.com/java/206/java-data-structure/alphanumeric-string-sorting-in-java-implementation/
Unfortunately I can only get that object to sort and I lose the other objects in my ArrayList
as a consequence. I really need a sorting algorithm that can rearrange the ArrayList
index's by the object of my choosing and not lose the other objects!
Is there a method to do this already out there? I've been unable to find one. I think it's useful to add that all the objects in my ArrayList
are mapped strings: ArrayList<HashMap<String, String>>
[edit]
I have my array:
ArrayList<HashMap<String, String>> al
I then store the object:
String[] alphaNumericStringArray = new String[al.size()];
for(int i = 0; i < al.size(); i++)
{
alphaNumericStringArray[i] = al.get(i).get("my_id");
}
I now sort the string array:
// Sort the array now.
Arrays.sort(alphaNumericStringArray, new AlphanumericSorting());
I then put the object back:
for(int i = 0; i < al.size(); i++)
{
HashMap<String, String> map = new HashMap<String, String>();
map.put("my_id", alphaNumericStringArray[i]);
// TODO, need to append the rest of the objects.
al.set(i, map);
}
I know what you're thinking, I'm not adding all the objects BACK when I re-map it. This is what I have currently, but what I want is a way to sort the whole list not just the one object "my_id". I want to rearrange the indexes so I don't have to re-map everything at the end.
Upvotes: 0
Views: 3631
Reputation: 1421
After careful reconstruction of the Comparator and all the comments I finally figured out how to do this.
Question:
To reiterate what my goal is, as well as the solution. I have an ArrayList<HashMap<String, String>>
. I want to sort the ArrayList by one object in the HashMap. My HashMap has more than 1 object in it so I want to retain the entire index of the Array. I also want to sort alphanumerically where numeric values are the first to be sorted, than I sort alphabetically. i.e., 1,2,3,4,... A,B,C,D,...
References: http://sanjaal.com/java/206/java-data-structure/alphanumeric-string-sorting-in-java-implementation/
TL;DR Solution:
In my custom Comparator function public int compare(object firstObj, Object secondObj)
I needed to change the String values to HashMap object references/values. Here the KEY_ID is the object that I wanted to sort by. Once I did this I used Collections.sort to sort by the HashMap comparator rather than the Arrays.sort (Collections handles ArrayList/HashMaps).
Code Solution:
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
/**
* DOCUMENTATION:
* http://sanjaal.com/java/206/java-data-structure/alphanumeric-string-sorting-in-java-implementation/
**/
@SuppressWarnings({"rawtypes", "unchecked"})
public class AlphanumericSorting implements Comparator
{
public int compare(Object firstObjToCompare, Object secondObjToCompare)
{
String firstString = ((HashMap<String,String>) firstObjToCompare).get("KEY_ID");
String secondString = ((HashMap<String,String>) secondObjToCompare).get("KEY_ID");
//String firstString = firstObjToCompare.toString();
//String secondString = secondObjToCompare.toString();
if (secondString == null || firstString == null)
{
return 0;
}
int lengthFirstStr = firstString.length();
int lengthSecondStr = secondString.length();
int index1 = 0;
int index2 = 0;
while(index1 < lengthFirstStr && index2 < lengthSecondStr)
{
char ch1 = firstString.charAt(index1);
char ch2 = secondString.charAt(index2);
char[] space1 = new char[lengthFirstStr];
char[] space2 = new char[lengthSecondStr];
int loc1 = 0;
int loc2 = 0;
do
{
space1[loc1++] = ch1;
index1++;
if (index1 < lengthFirstStr)
{
ch1 = firstString.charAt(index1);
}
else
{
break;
}
}
while (Character.isDigit(ch1) == Character.isDigit(space1[0]));
do
{
space2[loc2++] = ch2;
index2++;
if (index2 < lengthSecondStr)
{
ch2 = secondString.charAt(index2);
} else
{
break;
}
}
while (Character.isDigit(ch2) == Character.isDigit(space2[0]));
String str1 = new String(space1);
String str2 = new String(space2);
int result;
if (Character.isDigit(space1[0]) && Character.isDigit(space2[0]))
{
Integer firstNumberToCompare = new Integer(Integer.parseInt(str1.trim()));
Integer secondNumberToCompare = new Integer(Integer.parseInt(str2.trim()));
result = firstNumberToCompare.compareTo(secondNumberToCompare);
}
else
{
result = str1.compareTo(str2);
}
if (result != 0)
{
return result;
}
}
return lengthFirstStr - lengthSecondStr;
}
/**
* ALPHANUMERIC SORTING
*/
public static ArrayList<HashMap<String, String>> sortArrayList(ArrayList<HashMap<String, String>> al)
{
Collections.sort(al, new AlphanumericSorting());
return al;
}
}
To return the sorted ArrayList:
myArrayList = AlphanumericSorting.sortArrayList(myArrayList);
Where,
ArrayList<HashMap<String, String>> myArrayList;
Upvotes: 0
Reputation: 64632
Running the main
method:
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
public class Sorter {
public static void main(String[] args) {
List<String> unsorted = Arrays.asList("1A", "10B", "B", "753c", "Z", "M7", "32x", "11B", "2C", "205Z");
Collections.sort(unsorted, new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
if (o1.isEmpty())
return -1;
if (o2.isEmpty())
return 1;
String o1number = extractNumberPrefix(o1);
String o2number = extractNumberPrefix(o2);
if (o1number.isEmpty())
if (o2number.isEmpty())
return o1.compareTo(o2);
else return 1;
if (o2number.isEmpty())
return -1;
if (o1number.equals(o2number))
return o1.compareTo(o2);
return Integer.parseInt(o1number) - Integer.parseInt(o2number);
}
private String extractNumberPrefix(String o1) {
String result = "";
for (int i = 0; i < o1.length(); i++) {
try {
Integer.parseInt(o1.substring(i, i + 1));
result += o1.substring(i, i + 1);
} catch (Exception e) {
break;
}
}
return result;
}
});
System.out.println("sorted = " + unsorted);
}
}
returns:
sorted = [1A, 2C, 10B, 11B, 32x, 205Z, 753c, B, M7, Z]
Upvotes: 2