CODEWITHSUNDEEP
python
Dev.K.
Dev.K.

Reputation: 2488

Python Octal Escape String

I'm doing a web application login automation. The web app prefix and suffix few octal escaped character with password , make md5 hash of the password at client side and send to server.

So when I Md5 encrypt the string using Java Script, I get below result.

The webapp uses https://ideone.com/2C1b5 JS lib for client side MD5 conversion. hexMD5() belongs to that lib.

enter image description here

But when I am trying to do the same using python I get different result. 

import hashlib
def getMd5(string):
    m = hashlib.md5()
    m.update(string)
    return m.hexdigest()
prefix = "\051"
suffix  = "\341\303\026\153\155\271\161\166\030\054\324\011\046\035\344\274"

prefix = unicode(prefix,'unicode-escape')
suffix = unicode(suffix,'unicode-escape')
salted = prefix+"HELLO"+suffix
print getMd5(salted.encode('utf8'))

Result 

c7862e873e9bc54a93aec58c199cda37

Can any one please explain what I'm doing wrong here ?

Upvotes: 2

Views: 863

Answers (2)

Padraic Cunningham
Padraic Cunningham

Reputation: 180532

import hashlib
def getMd5(string):
    m = hashlib.md5()
    m.update(string)
    return m.hexdigest()
prefix = "\051"
suffix  ="\341\303\026\153\155\271\161\166\030\054\324\011\046\035\344\274"


salted = prefix+"HELLO"+suffix
print getMd5(salted)

37a0c199850b36090b439c3ac152fd70

Not using unicode gives the same output as your Javascript.

If I understand your comment correctly:

len(r"\051") == 4 # use raw string r
len("\051") == 1

Upvotes: 2

MrM
MrM

Reputation: 21

this question is old but I came across with this problem a few day ago and above answer couldn't solve it, so I solved it in this way.

1- first convert all character to octal equal format

HELLO => \110\105\114\114\117

by this functions stringToOctal

def dectoOct(decimal):
    octal = 0
    ctr = 0
    temp = decimal
    while (temp > 0):
        octal += ((temp % 8) * (10 ** ctr))
        temp = int(temp / 8)
        ctr += 1
    return octal

def stringToOctal(string):
    result = ""
    for character in list(string):
        result += "\\"+ str(dectoOct(ord(character)))
    return result

then result shuold be something like

\051\110\105\114\114\117\341\303\026\153\155\271\161\166\030\054\324\011\046\035\344\274

2- convert octal numbers to bytes

final code is some thing like:

import hashlib

def dectoOct(decimal):
    octal = 0
    ctr = 0
    temp = decimal
    while (temp > 0):
        octal += ((temp % 8) * (10 ** ctr))
        temp = int(temp / 8)
        ctr += 1
    return octal

def stringToOctal(string):
    result = ""
    for character in list(string):
        result += "\\"+ str(dectoOct(ord(character)))
    return result

prefix = r"\051"
suffix  =r"\341\303\026\153\155\271\161\166\030\054\324\011\046\035\344\274"
word = "HELLO"


octalCharacters = prefix + stringToOctal(word) + suffix

hashed = hashlib.md5(bytes([int(i, 8) for i in octalCharacters.split("\\")[1:]]))

result = hashed.hexdigest()

Result:

37a0c199850b36090b439c3ac152fd70

Upvotes: 0

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