CODEWITHSUNDEEP
pythondatetimepython-2.4
user4613285
user4613285

Reputation:

Display given datetime in reverse order in python

I have a date timestamp like "2013-12-20 23:40:33". Now, my requirement is to re-format this date in reverse order like : 

<seconds><minutes><hr><day><month><year>

in python. Please suggest

Upvotes: 0

Views: 9039

Answers (4)

George
George

Reputation: 11

d = "2013-12-20 23:40:33"  
date = d[17]+d[18]+":"+d[14]+d[15]+":"+d[11]+d[12]+" "+d[8]+d[9]+"-"+d[5]+d[6]+"-"+d[0]+d[1]+d[2]+d[3]  
print(d)  
print(date)

Upvotes: 0

jfs
jfs

Reputation: 414585

If you don't need to validate the time string:

>>> import re
>>> '<%s>' % '><'.join(re.findall(r'\d+', "2013-12-20 23:40:33")[::-1])
'<33><40><23><20><12><2013>'

It is 6 times faster than the corresponding datetime solution:

>>> from datetime import datetime
>>> datetime.strptime("2013-12-20 23:40:33", '%Y-%m-%d %H:%M:%S').strftime('<%S><%M><%H><%d><%m><%Y>')
'<33><40><23><20><12><2013>'

Or 5 times faster than time solution:

>>> import time
>>> time.strftime('<%S><%M><%H><%d><%m><%Y>', time.strptime("2013-12-20 23:40:33", '%Y-%m-%d %H:%M:%S'))
'<33><40><23><20><12><2013>'

Upvotes: 2

alecxe
alecxe

Reputation: 474001

Load the string into a datetime object with strptime and format to string with strftime:

>>> from datetime import datetime
>>> datetime.strptime(s, '%Y-%m-%d %H:%M:%S').strftime('%S:%M:%H %d-%m-%Y')
'33:40:23 20-12-2013'

Upvotes: 5

jamylak
jamylak

Reputation: 133634

>>> import datetime
>>> datetime.datetime.strptime('2013-12-20 23:40:33', '%Y-%m-%d %H:%M:%S').strftime('%S:%M:%H %d-%m-%Y')
'33:40:23 20-12-2013'

Upvotes: 3

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