CODEWITHSUNDEEP
rplotlegend
user3813057
user3813057

Reputation: 911

title position in legend in R plot

I use the following code to draw a plot.

x = seq(-20,20,by=0.2);
c = .2;
y1 = exp(c*x);
c = .5;
y2 = exp(c*x);
c = 1;
y3 = exp(c*x);
par(mgp = c(2,.5,0));   # to adjust dist of x/y label to plot, x/y axes to plot
plot(x,
     y1,
     type="l",
     xlab=expression(x-theta),
     ylab=expression(L(x,theta)),
     main="function");
lines(x,y2,col="blue");
lines(x,y3,col="green");
legend(x=-20,
       y=40,
       title=expression(L(x, theta)==e^{c(x-theta)}),
       legend=expression("c=.2", "c=.5", "c=1"),
       lty=c(1, 1, 1),
       lwd=c(2.5, 2.5,2.5),
       col=c("black","blue","green"));

I find that the brackets of $(x-\theta)$ in the legend exceed the box. Is there any way to move that expression down? I tried replacing the original legend function by

legend(x=-20,y=40,title.adj=c(0,.5), title=expression(L(x,theta)==e^{c(x-theta)}), legend=expression("c=.2","c=.5","c=1"), lty=c(1,1,1), lwd=c(2.5,2.5,2.5), col=c("black","blue","green"));

However, the expression appeared twice in the legend box.

Thanks!

Upvotes: 0

Views: 1676

Answers (1)

Jthorpe
Jthorpe

Reputation: 10196

I think it looks better without a box ( legend( ... ,bty='n') ) but if you really want a box, here's how you do it:

lgnd = legend(x=-20,
               y=40,
               title=expression(L(x, theta)==e^{c(x-theta)}),
               legend=expression("c=.2", "c=.5", "c=1"),
               lty=c(1, 1, 1),
               lwd=c(2.5, 2.5,2.5),
               col=c("black","blue","green"),
               # no box
               bty='n');

# plot your own box using the lgnd$rect as your starting point
params = lgnd$rect
rect(xleft = params[['left']],
    ybottom = params[['top']] - params[['h']],
    xright = params[['left']] + params[['w']],
    ytop = params[['top']] + 1)

Upvotes: 1

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