CODEWITHSUNDEEP
phpjqueryajax
Pekka
Pekka

Reputation: 1115

ajax jquery get value of data from php

[{
    "SchoolId":"015-08-0034-009-37",
    "SubjectId":"08-0034-00613",
    "Student":[
        {"StudentId":"T-15981","StudentName":"John"},
        {"StudentId":"T-15982","StudentName":"Paul"}
    ]
}]

I have a json format like this one from my php json_encode. I am getting the data like this 

for (var i = 0; i < data.length; i++) {
     console.log(data.[i].SchoolId);
     console.log(data.[i].SubjectId);
}

and i want to get the value of 

 {"StudentId":"T-15981","StudentName":"John"},
 {"StudentId":"T-15982","StudentName":"Paul"}

How to get the value of the two entries?Any idea is appreciated

UPDATE

success: function(data) {


    for (var i = 0; i < data.student.length; i++) {
        console.log(data.student[i].StudentId);
        console.log(data.student[i].SchoolId);
    }
},

this is a print_r i got from ajax response by changing datatype from json to html.this is the output in network>XHR>Response

Array
(
    [0] => Array
        (
            [SchoolId] => 015-08-0034-009-37
            [SubjectId] => 08-0034-00613
            [Student] => Array
                (
                    [0] => Array
                        (
                            [StudentId] => 015-08-0034-009-37
                            [firstname] => Chona
                            [lastname] => Sy
                            [middleinitial] => D
                        )

                    [1] => Array
                        (
                            [StudentId] => 015-08-0034-009-37
                            [firstname] => Alona
                            [lastname] => Sy
                            [middleinitial] => D
                        )

                )

        )

    [1] => Array
        (
            [SchoolId] => 015-08-0034-009-38
            [SubjectId] => 08-0034-00613
            [SupersededProperty] => Array
                (
                    [0] => Array
                        (
                            [StudentId] => 015-08-0034-009-36
                            [firstname] => Edith
                            [lastname] => Sy
                            [middleinitial] => D
                        )

                )

        )

)

Upvotes: 1

Views: 115

Answers (3)

Miro
Miro

Reputation: 8660

You problem is that you have an array inside an array. This results in the square brackets [{...}] around your json.

Array
(
    [0] => Array
        (
...

You shouldn't echo the first array.

For example it seems like now you have 

echo json_encode(array($data));

And instead you should have

echo json_encode($data);

As a last resorst try echoing $data[0];

Also see this

Upvotes: 0

MyTwoCents
MyTwoCents

Reputation: 7622

var data = [{
    "SchoolId":"015-08-0034-009-37",
    "SubjectId":"08-0034-00613",
    "Student":[
        {"StudentId":"T-15981","StudentName":"John"},
        {"StudentId":"T-15982","StudentName":"Paul"}
    ]
}] 

for(var i=0; i<data[0].Student.length; i++){
  var StudentData = data[0].Student[i];
   alert(StudentData.StudentId); 
}

Upvotes: 0

Lumi Lu
Lumi Lu

Reputation: 3305

You can find working example in FIDDLE

JS code

var e = {
    "Student":[
        {"StudentId":"T-15981","StudentName":"John"},
        {"StudentId":"T-15982","StudentName":"Paul"}
    ], 
    "SchoolId":"015-08-0034-009-37",
    "SubjectId":"08-0034-00613",
};


for(var i=0; i<e.Student.length; i++){
  alert('StudentId = ' + e.Student[i].StudentId + '; StudentName = ' + e.Student[i].StudentName);   
}

Upvotes: 1

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