CODEWITHSUNDEEP
c
Rajesh
Rajesh

Reputation: 31

iso c90 forbids mixed declarations and code

This is my coding and I am getting the above error in the line where i declared int *intpointer. Please help me in solving this.

#include <stdio.h>

int main()
{
int intarray[5] = {10,20,30,40,50};

int i;
for(i = 0; i < 5; i++)
    printf("intarray[%d] has value: %d - and address @ %x\n", i,     intarray[i], &intarray[i]);

int *intpointer = &intarray[4];
printf("address: %x - has value %d\n", intpointer, *intpointer); 

intpointer--;
printf("address: %x - has value %d\n", intpointer, *intpointer); 

return 0;
}

Upvotes: 1

Views: 1336

Answers (1)

Vlad from Moscow
Vlad from Moscow

Reputation: 310990

Place this declaration

int *intpointer = &intarray[4];

in the beginning of the function code block after the declaration of intarray.

As error message reports you compile your code as C90 code that requires that declarations would be before other statements.

Upvotes: 2

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