Reputation: 1049
How to return rows where a column has 2 words (that is, strings separated by a space) in it?
It must be purely using SQL.
SELECT * FROM table WHERE name (has 2 strings in it);
Upvotes: 5
Views: 3569
Reputation: 376
Use % between words. Example:
SELECT * FROM Table WHERE Col LIKE '%word1%word2%'
Upvotes: 0
Reputation: 3623
This perfectly works for me
You can use 'AND' condition and Like Operator with wildcards (%).
SELECT * FROM table_name WHERE name LIKE '%Word1%' AND name LIKE '%Word2%'
Upvotes: 4
Reputation: 726839
I dont know the names when querying. Its a big dataset. I only have to check if the name contains a spacebar basically (from a comment).
If you want to distinguish names that have two parts from one-part and three-plus-part names, you can use regular expression:
SELECT * FROM my_table WHERE name REGEXP '^[^ ]+[ ]+[^ ]+$'
This regular expression matches when the entire string consists of two non-empty parts containing no spaces, with one or more space separating them.
Upvotes: 6
Reputation: 44864
You can use the following technique
mysql> select length('first name')-length(replace('first name',' ','')) as diff;
+------+
| diff |
+------+
| 1 |
+------+
i.e. get the difference of actual name and the name after replacing space, and if its 1 then you have the value as firstname lastname
So the query may look like
select * from table
where
length(col_name)-length(replace(col_name,' ','')) = 1
Upvotes: 0
Reputation: 44796
SELECT * FROM table WHERE concat(' ',name,' ') like '% str1 %'
AND concat(' ',name,' ') like '% str2 %'
The extra blanks are there to separate words.
Upvotes: 0
Reputation: 31785
How about simply:
...
WHERE [name] LIKE '%Word1%'
AND [name] LIKE '%Word2%'
Upvotes: 0