CODEWITHSUNDEEP
javascriptfunctionreturn
Jonas
Jonas

Reputation: 3

Function inside function vs function returns function in JavaScript

I am studying JavaScript and I can't understand this.

function Out1()
{
    function In1()
        {
            console.log("text inside function In1");
        }
    return In1();
}


function Out2()
{
    return function In2()
        {
            console.log("text inside function In2");
        };
}

Out1();    // text inside function In1
Out2();    //

Out2(); outputs nothing in console. What I am doing wrong?

Upvotes: 0

Views: 453

Answers (1)

T.J. Crowder
T.J. Crowder

Reputation: 1074355

Out2(); outputs nothing in console. What I am doing wrong?

Out2 returns a reference to the function it created. It doesn't call that function. You could call it by using () on the returned reference:

//  vv-------- These call `Out2`   
Out2()();
//    ^^------ These call the function referenced returned by `Out2`

E.g.:

var f = Out2(); // `f` is now a reference to the `In2` function
f();            // This calls `In2`

Upvotes: 1

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