Reputation: 11626
I am looking for some SQL varchar comparison function like C# string.compare (we can ignore case for now, should return zero when the character expression are same and a non zero expression when they are different)
Basically I have some alphanumeric column in one table which needs to be verified in another table.
I cannot do select A.col1 - B.col1 from (query) as "-" operator cannot be applied on character expressions
I cannot cast my expression as int (and then do a difference/subtraction) as it fails
select cast ('ASXT000R' as int)
Conversion failed when converting varchar 'ASXT000R' to int
Soundex
would not do it as soundex is same for 2 similar strings
Difference
would not do it as select difference('abc','ABC')
= 4 (as per msdn, difference is the difference in the soundex of 2 character expressions and difference =4 implies least different)
I can write a curson to do ascii comparison for each alphanumeric character in each row, but I was wondering if there is any other way of doing it ?
Upvotes: 3
Views: 43975
Reputation: 630
select case when a.col1 = b.col1 then 0 else 1 end from a join b on a.id = b.id
or
select case when lower(a.col1) = lower(b.col1) then 0 else 1 end from a join b on a.id = b.id
Upvotes: 1
Reputation: 838236
we can ignore case for now, should return zero when the character expression are same and a non zero expression when they are different
If that's all you want, you can just use this:
CASE WHEN 'a' = 'b' THEN 0 ELSE 1 END
Note that this expression returns 1 when either of the arguments is NULL. This is probably not what you want. You can use the following to return NULL if either argument is NULL:
CASE WHEN 'a' = 'b' THEN 0
WHEN 'a' <> 'b' THEN 1
END
If you want negative and positive values depending on which compares 'larger', you could use this instead:
CASE WHEN 'a' < 'b' THEN -1
WHEN 'a' = 'b' THEN 0
WHEN 'a' > 'b' THEN 1
END
Upvotes: 3