CODEWITHSUNDEEP
c#static
Rohit
Rohit

Reputation: 10236

How is the method called in static class

My code is as follows

   class MyStaticClass
   {

     static MyStaticClass{};

    public static readonly MyStaticClass Instance = CreateMe();
    public static int GetSomeValue = GetValue();

    private static int GetValue()
    {
        return 0;
    }

    private static MyStaticClass CreateMe()
    {
        Console.WriteLine("This method was called");
        return new MyStaticClass();
    }

}

public class Program {

    public static void Main()
    {

         int val=MyStaticClass.GetSomeValue;

    }
 }

O/p:

This method was called

When I call val why does the debugger accesses CreateMe method ? Is it that any static method I access it will access all the static methods in the class ?

Upvotes: 2

Views: 89

Answers (3)

Christopher Stevenson
Christopher Stevenson

Reputation: 2861

You have a static initializer for a static field. As part of program startup, all static fields are evaluated.

Edit: small clarification here:

The static fields in a particular class are evaluated in declaration order, but there in no particular order for which class has it's static fields initialized first. Now, if you had a static property, that would be different.

MSDN link

Upvotes: 1

denys-vega
denys-vega

Reputation: 3697

Both fields have been initialized using the static methods. So, in that case, all the static methods will be evaluated.

Upvotes: 0

Adil
Adil

Reputation: 148110

The method CreateMe() is called because you are calling in when you create object Instance in the following statement. 

 public static readonly MyStaticClass Instance = CreateMe();

This is static object in your class and is created as you access the class which you did by MyStaticClass.GetSomeValue.

Dubugging the code will give you clear view of the order of the statements get executed. You can go through this detailed article on MSDN regarding debugging Debugger Roadmap

Upvotes: 4

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