Reputation: 333
I have the following table ("Table") format
A B C
"801331" "5755270" "0"
"1761861" "10556391" "1"
"1761861" "10557381" "33"
"1761861" "11069131" "33"
"801331" "24348751" "0"
"801331" "77219852" "0"
"1761861" "557880972" "0"
And I would like to count and present two different quantities in one table grouped by column A.
The first is:
SELECT A, COUNT(*) FROM Table GROUP BY A
The second one has one condition:
SELECT A, COUNT(*) FROM Table WHERE C != 0 GROUP BY A
I want to have the following result
A 1st 2nd
"1761861" "4" "3"
"801331" "3" "0"
I tried a few answers from questions such as thisOne yet I could not make it happen as the result is one row.
I get it is pretty easy, yet i cannot make it work.
Is there a (simple) way to do it?
Upvotes: 0
Views: 147
Reputation: 832
SELECT A, sum(1), sum(case when C <> 0 then 1 else 0 end) FROM Table GROUP BY A;
SELECT A, count(*), count(case when C <> 0 then A else null end) FROM Table GROUP BY A;
Upvotes: 1