How do you sort a dictionary by value?

Question

I often have to sort a dictionary (consisting of keys & values) by value. For example, I have a hash of words and respective frequencies that I want to order by frequency.

There is a SortedList which is good for a single value (say frequency), that I want to map back to the word.

SortedDictionary orders by key, not value. Some resort to a custom class, but is there a cleaner way?

Answer 1

You could use:

var ordered = dict.OrderBy(x => x.Value);

Answer 2

The following code snippet sorts a Dictionary by values.

The code first creates a dictionary and then uses OrderBy method to sort the items.

public void SortDictionary()  
{  
  
    // Create a dictionary with string key and Int16 value pair  
    Dictionary<string, Int16> AuthorList = new Dictionary<string, Int16>();  
    AuthorList.Add("Mahesh Chand", 35);  
    AuthorList.Add("Mike Gold", 25);  
    AuthorList.Add("Praveen Kumar", 29);  
    AuthorList.Add("Raj Beniwal", 21);  
    AuthorList.Add("Dinesh Beniwal", 84);   
  
    // Sorted by Value  
  
    Console.WriteLine("Sorted by Value");  
    Console.WriteLine("=============");  
    foreach (KeyValuePair<string, Int16> author in AuthorList.OrderBy(key => key.Value))  
    {  
        Console.WriteLine("Key: {0}, Value: {1}", author.Key, author.Value);  
    }  
} 

Answer 3

Suppose we have a dictionary as:

Dictionary<int, int> dict = new Dictionary<int, int>();
dict.Add(21,1041);
dict.Add(213, 1021);
dict.Add(45, 1081);
dict.Add(54, 1091);
dict.Add(3425, 1061);
dict.Add(768, 1011);

You can use temporary dictionary to store values as:

Dictionary<int, int> dctTemp = new Dictionary<int, int>();
foreach (KeyValuePair<int, int> pair in dict.OrderBy(key => key.Value))
{
    dctTemp.Add(pair.Key, pair.Value);
}

Answer 4

Best way:

var list = dict.Values.OrderByDescending(x => x).ToList();
var sortedData = dict.OrderBy(x => list.IndexOf(x.Value));

Answer 5

You can sort a Dictionary by value and save it back to itself (so that when you foreach over it the values come out in order):

dict = dict.OrderBy(x => x.Value).ToDictionary(x => x.Key, x => x.Value);

Sure, it may not be correct, but it works. Hyrum's Law means that this will very likely continue to work.

Answer 6

You could use:

Dictionary<string, string> dic= new Dictionary<string, string>();
var ordered = dic.OrderBy(x => x.Value);
return ordered.ToDictionary(t => t.Key, t => t.Value);

Answer 7

Sort and print:

var items = from pair in players_Dic
                orderby pair.Value descending
                select pair;

// Display results.
foreach (KeyValuePair<string, int> pair in items)
{
    Debug.Log(pair.Key + " - " + pair.Value);
}

Change descending to acending to change sort order

Answer 8

Actually in C#, dictionaries don't have sort() methods. As you are more interested in sort by values, you can't get values until you provide them key. In short, you need to iterate through them using LINQ's OrderBy(),

var items = new Dictionary<string, int>();
items.Add("cat", 0);
items.Add("dog", 20);
items.Add("bear", 100);
items.Add("lion", 50);

// Call OrderBy() method here on each item and provide them the IDs.
foreach (var item in items.OrderBy(k => k.Key))
{
    Console.WriteLine(item);// items are in sorted order
}

You can do one trick:

var sortedDictByOrder = items.OrderBy(v => v.Value);

or:

var sortedKeys = from pair in dictName
            orderby pair.Value ascending
            select pair;

It also depends on what kind of values you are storing: single (like string, int) or multiple (like List, Array, user defined class). If it's single you can make list of it and then apply sort.
If it's user defined class, then that class must implement IComparable, ClassName: IComparable<ClassName> and override compareTo(ClassName c) as they are more faster and more object oriented than LINQ.

Answer 9

The easiest way to get a sorted Dictionary is to use the built in SortedDictionary class:

//Sorts sections according to the key value stored on "sections" unsorted dictionary, which is passed as a constructor argument
System.Collections.Generic.SortedDictionary<int, string> sortedSections = null;
if (sections != null)
{
    sortedSections = new SortedDictionary<int, string>(sections);
}

sortedSections will contain the sorted version of sections

Answer 10

Required namespace : using System.Linq;

Dictionary<string, int> counts = new Dictionary<string, int>();
counts.Add("one", 1);
counts.Add("four", 4);
counts.Add("two", 2);
counts.Add("three", 3);

Order by desc :

foreach (KeyValuePair<string, int> kvp in counts.OrderByDescending(key => key.Value))
{
// some processing logic for each item if you want.
}

Order by Asc :

foreach (KeyValuePair<string, int> kvp in counts.OrderBy(key => key.Value))
{
// some processing logic for each item if you want.
}

Answer 11

On a high level, you have no other choice than to walk through the whole Dictionary and look at each value.

Maybe this helps: http://bytes.com/forum/thread563638.html Copy/Pasting from John Timney:

Dictionary<string, string> s = new Dictionary<string, string>();
s.Add("1", "a Item");
s.Add("2", "c Item");
s.Add("3", "b Item");

List<KeyValuePair<string, string>> myList = new List<KeyValuePair<string, string>>(s);
myList.Sort(
    delegate(KeyValuePair<string, string> firstPair,
    KeyValuePair<string, string> nextPair)
    {
        return firstPair.Value.CompareTo(nextPair.Value);
    }
);

Answer 12

You'd never be able to sort a dictionary anyway. They are not actually ordered. The guarantees for a dictionary are that the key and value collections are iterable, and values can be retrieved by index or key, but there is no guarantee of any particular order. Hence you would need to get the name value pair into a list.

Answer 13

The other answers are good, if all you want is to have a "temporary" list sorted by Value. However, if you want to have a dictionary sorted by Key that automatically synchronizes with another dictionary that is sorted by Value, you could use the Bijection<K1, K2> class.

Bijection<K1, K2> allows you to initialize the collection with two existing dictionaries, so if you want one of them to be unsorted, and you want the other one to be sorted, you could create your bijection with code like

var dict = new Bijection<Key, Value>(new Dictionary<Key,Value>(), 
                               new SortedDictionary<Value,Key>());

You can use dict like any normal dictionary (it implements IDictionary<K, V>), and then call dict.Inverse to get the "inverse" dictionary which is sorted by Value.

Bijection<K1, K2> is part of Loyc.Collections.dll, but if you want, you could simply copy the source code into your own project.

Note: In case there are multiple keys with the same value, you can't use Bijection, but you could manually synchronize between an ordinary Dictionary<Key,Value> and a BMultiMap<Value,Key>.

Answer 14

Sorting a SortedDictionary list to bind into a ListView control using VB.NET:

Dim MyDictionary As SortedDictionary(Of String, MyDictionaryEntry)

MyDictionaryListView.ItemsSource = MyDictionary.Values.OrderByDescending(Function(entry) entry.MyValue)

Public Class MyDictionaryEntry ' Need Property for GridViewColumn DisplayMemberBinding
    Public Property MyString As String
    Public Property MyValue As Integer
End Class

XAML:

<ListView Name="MyDictionaryListView">
    <ListView.View>
        <GridView>
            <GridViewColumn DisplayMemberBinding="{Binding Path=MyString}" Header="MyStringColumnName"></GridViewColumn>
            <GridViewColumn DisplayMemberBinding="{Binding Path=MyValue}" Header="MyValueColumnName"></GridViewColumn>
         </GridView>
    </ListView.View>
</ListView>

Answer 15

Use LINQ:

Dictionary<string, int> myDict = new Dictionary<string, int>();
myDict.Add("one", 1);
myDict.Add("four", 4);
myDict.Add("two", 2);
myDict.Add("three", 3);

var sortedDict = from entry in myDict orderby entry.Value ascending select entry;

This would also allow for great flexibility in that you can select the top 10, 20 10%, etc. Or if you are using your word frequency index for type-ahead, you could also include StartsWith clause as well.

Answer 16

Use:

using System.Linq.Enumerable;
...
List<KeyValuePair<string, string>> myList = aDictionary.ToList();

myList.Sort(
    delegate(KeyValuePair<string, string> pair1,
    KeyValuePair<string, string> pair2)
    {
        return pair1.Value.CompareTo(pair2.Value);
    }
);

Since you're targeting .NET 2.0 or above, you can simplify this into lambda syntax -- it's equivalent, but shorter. If you're targeting .NET 2.0 you can only use this syntax if you're using the compiler from Visual Studio 2008 (or above).

var myList = aDictionary.ToList();

myList.Sort((pair1,pair2) => pair1.Value.CompareTo(pair2.Value));

Answer 17

Given you have a dictionary you can sort them directly on values using below one liner:

var x = (from c in dict orderby c.Value.Order ascending select c).ToDictionary(c => c.Key, c=>c.Value);

Answer 18

You do not sort entries in the Dictionary. Dictionary class in .NET is implemented as a hashtable - this data structure is not sortable by definition.

If you need to be able to iterate over your collection (by key) - you need to use SortedDictionary, which is implemented as a Binary Search Tree.

In your case, however the source structure is irrelevant, because it is sorted by a different field. You would still need to sort it by frequency and put it in a new collection sorted by the relevant field (frequency). So in this collection the frequencies are keys and words are values. Since many words can have the same frequency (and you are going to use it as a key) you cannot use neither Dictionary nor SortedDictionary (they require unique keys). This leaves you with a SortedList.

I don't understand why you insist on maintaining a link to the original item in your main/first dictionary.

If the objects in your collection had a more complex structure (more fields) and you needed to be able to efficiently access/sort them using several different fields as keys - You would probably need a custom data structure that would consist of the main storage that supports O(1) insertion and removal (LinkedList) and several indexing structures - Dictionaries/SortedDictionaries/SortedLists. These indexes would use one of the fields from your complex class as a key and a pointer/reference to the LinkedListNode in the LinkedList as a value.

You would need to coordinate insertions and removals to keep your indexes in sync with the main collection (LinkedList) and removals would be pretty expensive I'd think. This is similar to how database indexes work - they are fantastic for lookups but they become a burden when you need to perform many insetions and deletions.

All of the above is only justified if you are going to do some look-up heavy processing. If you only need to output them once sorted by frequency then you could just produce a list of (anonymous) tuples:

var dict = new SortedDictionary<string, int>();
// ToDo: populate dict

var output = dict.OrderBy(e => e.Value).Select(e => new {frequency = e.Value, word = e.Key}).ToList();

foreach (var entry in output)
{
    Console.WriteLine("frequency:{0}, word: {1}",entry.frequency,entry.word);
}

Answer 19

Looking around, and using some C# 3.0 features we can do this:

foreach (KeyValuePair<string,int> item in keywordCounts.OrderBy(key=> key.Value))
{ 
    // do something with item.Key and item.Value
}

This is the cleanest way I've seen and is similar to the Ruby way of handling hashes.

Answer 20

You can sort the Dictionary by value and get the result in dictionary using the code below:

Dictionary <<string, string>> ShareUserNewCopy = 
       ShareUserCopy.OrderBy(x => x.Value).ToDictionary(pair => pair.Key,
                                                        pair => pair.Value);                                          

Answer 21

Or for fun you could use some LINQ extension goodness:

var dictionary = new Dictionary<string, int> { { "c", 3 }, { "a", 1 }, { "b", 2 } };
dictionary.OrderBy(x => x.Value)
  .ForEach(x => Console.WriteLine("{0}={1}", x.Key,x.Value));