Reputation: 1655
I'm trying to display two bitmaps of the same image in the view at different location as shown below, but it's showing only the first one. If I comment out the first one then the other one is displayed.
void CChildView::OnPaint()
{
// Load the bitmap
CBitmap BmpLady;
// Load the bitmap from the resource
BmpLady.LoadBitmap(IDB_MB);
CPaintDC dc(this); // device context for painting
// Create a memory device compatible with the above CPaintDC variable
CDC MemDCLady;
MemDCLady.CreateCompatibleDC(&dc);
// Select the new bitmap
CBitmap *BmpPrevious = MemDCLady.SelectObject(&BmpLady);
// Copy the bits from the memory DC into the current dc
dc.BitBlt(20, 10, 436, 364, &MemDCLady, 0, 0, SRCCOPY);
// Restore the old bitmap
dc.SelectObject(BmpPrevious);
// Draw another bitmap for same image.
CPaintDC dc1(this);
CDC MemDCLady1;
MemDCLady1.CreateCompatibleDC(&dc1);
CBitmap *BmpPrevious1 = MemDCLady1.SelectObject(&BmpLady);
dc1.BitBlt(200, 100, 436, 364, &MemDCLady1, 0, 0, SRCCOPY);
dc1.SelectObject(BmpPrevious1);
}
How to display both the images simultaneously? Please help. Thanks in advance.
P.S: I'm fairly new to MFC.
Upvotes: 1
Views: 1957
Reputation: 1655
There is no need to CreateCompatibleDC again for the second bitmap. With the following changes I'm able to display both the bitmaps simultaneously
void CChildView::OnPaint()
{
CBitmap BmpLady;
// Load the bitmap from the resource
BmpLady.LoadBitmap(IDB_MB);
CPaintDC dc(this);
CDC MemDCLady;
// Create a memory device compatible with the above CPaintDC variable
MemDCLady.CreateCompatibleDC(&dc);
// Select the new bitmap
//CBitmap *BmpPrevious = MemDCLady.SelectObject(&BmpLady);
MemDCLady.SelectObject(&BmpLady);
// Copy the bits from the memory DC into the current dc
dc.BitBlt(20, 10, 436, 364, &MemDCLady, 0, 0, SRCCOPY);
// MemDCLady.SelectObject(&BmpLady);
// Copy the bits from the memory DC into the current dc
dc.BitBlt(200, 100, 436, 364, &MemDCLady, 0, 0, SRCCOPY);
}
Upvotes: 3