Reputation: 3221
I need to produce an output as below. For each item in @ViewBag.Table, duplicate 3 times and then increment the value i by 1 for each foreach iteration
eg:
Values return by @ViewBag.Table { "Test", "AA", "Hello" }
Output:
Test 1
Test 2
Test 3
AA 4
AA 5
AA 6
Hello 7
Hello 8
Hello 9
How could this be done?
@foreach(var item in @ViewBag.Table)
{
for (int j = 1; j <= 3; j++)
{
@item.Column1 + " " + i;
}
}
Upvotes: 2
Views: 5629
Reputation: 12324
You can increment i
anywhere inside the foreach
loop, you can even do it on the same line where you assign it's value:
@{int i = 1;}
@foreach(var item in @ViewBag.Table)
{
for (int j = 1; j <= 3; j++)
{
@item.Column1 + " " + i++;
}
}
PS. As Ceisc mentioned, a standard way to start begin the loop is to start it from 0.
Upvotes: 7