Reputation: 13660
I start with tree plots:
df = pd.DataFrame([1,20,3],[2,30,4],[3,40,5],columns=['mean','size','stat'])
fig,[ax1,ax2,ax3] = plt.subplots(1, 3, sharey=True)
ax1.barh(np.arange(len(df)),df['mean'].values, align='center')
ax2.barh(np.arange(len(df)),df['size'].values, align='center')
ax3.barh(np.arange(len(df)),df['stat'].values, align='center')
Is there a way to rotate the x axis labels on all three plots?
Upvotes: 4
Views: 10579
Reputation: 436
You can do it for each ax your are creating:
ax1.xaxis.set_tick_params(rotation=90)
ax2.xaxis.set_tick_params(rotation=90)
ax3.xaxis.set_tick_params(rotation=90)
or you do it inside a for before showing the plot if you are building your axs using subplots:
for s_ax in ax:
s_ax.xaxis.set_tick_params(rotation=90)
Upvotes: 5
Reputation: 1074
Here is another more generic solution: you can just use axes.flatten() which will provide you with much more flexibility when you have higher dimensions.
for i, ax in enumerate(axes.flatten()):
sns.countplot(x= cats.iloc[:, i], orient='v', ax=ax)
for label in ax.get_xticklabels():
# only rotate one subplot if necessary.
if i==3:
label.set_rotation(90)
fig.tight_layout()
Upvotes: 0
Reputation: 4030
When you're done plotting, you can just loop over each xticklabel:
for ax in [ax1,ax2,ax3]:
for label in ax.get_xticklabels():
label.set_rotation(90)
Upvotes: 8
Reputation: 715
df = pd.DataFrame([1,20,3],[2,30,4],[3,40,5],columns=['mean','size','stat'])
fig,[ax1,ax2,ax3] = plt.subplots(1, 3, sharey=True)
plt.subplot(1,3,1)
barh(np.arange(len(df)),df['mean'].values, align='center')
locs, labels = xticks()
xticks(locs, labels, rotation="90")
plt.subplot(1,3,2)
barh(np.arange(len(df)),df['size'].values, align='center')
locs, labels = xticks()
xticks(locs, labels, rotation="90")
plt.subplot(1,3,3)
barh(np.arange(len(df)),df['stat'].values, align='center')
locs, labels = xticks()
xticks(locs, labels, rotation="90")
Should do the trick.
Upvotes: 2