CODEWITHSUNDEEP
swift
Mike D
Mike D

Reputation: 605

Swift how to format a large number with thousands separators?

Is there a simple command to format 1.60543e+06 to 1,605,436???

resultFV.text = String.localizedStringWithFormat("%f", fv)

does not get it.

Upvotes: 27

Views: 30708

Answers (8)

sean woodward
sean woodward

Reputation: 1783

Updated

Using Data Formatting available in Foundation for macOS 12.0+, iOS 15.0+, tvOS 15.0+, and watchOS 8.0+.

  let number: Int = 1000  
  let formatted = number.formatted(.number.grouping(.never))  
  print(formatted)

console output: "1000"

number can be any BinaryFloatingPoint or BinaryInteger

Upvotes: 0

user2399452
user2399452

Reputation: 53

Update for Swift 5

var unformattedValue : Double = 3534234.55
var formatter = NumberFormatter()
formatter.numberStyle = .currency // or .decimal if desired
formatter.maximumFractionDigits = 2; //change as desired
formatter.locale = Locale.current // or = Locale(identifier: "de_DE"), more locale identifier codes: https://gist.github.com/jacobbubu/1836273
var displayValue : String = formatter.string(from: NSNumber(value: unformattedValue))! // displayValue: "$3,534,235" ```

Upvotes: 5

Jon Willis
Jon Willis

Reputation: 7024

You can achieve this by using String initializers in Swift 3+:

// 1605436
let value: Int = 1605436

// "1,605,436" where Locale == en_US
let formattedInt = String(format: "%d", locale: Locale.current, value) 

// "1,605,436" where Locale == en_US
let formattedDouble = String(format: "%.0f", locale: Locale.current, Double(value))

Upvotes: 10

Hannes
Hannes

Reputation: 3772

You should use a NumberFormatter for that:

let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = .decimal

resultFV.text = numberFormatter.string(from: fv)

Upvotes: 23

Oleh Veheria
Oleh Veheria

Reputation: 412

Update for Swift 4.1 currency string:

let balance = 1234567

let formatter = NumberFormatter()
formatter.numberStyle = .currency
formatter.maximumFractionDigits = 0

let result = formatter.string(from: NSNumber(value: balance)) 
// result: $1,234,567

You can change formatter.numberStyle to .decimal to leave it as number without "$" sign.

Upvotes: 11

Mike D
Mike D

Reputation: 605

Swift Xcode 6.3, SOLVED (I decided to leave the $ in the code). If you don't want a $ in the output, change .CurrencyStyle to .DecimalStyle

var fv = 3534234.55 
var formatter = NSNumberFormatter()
formatter.numberStyle = .CurrencyStyle
formatter.maximumFractionDigits = 0;
resultFV.text = formatter.stringFromNumber(fv) // result: $3,534,235 –

Upvotes: 26

JLundell
JLundell

Reputation: 1610

In Swift 3,

NumberFormatter.localizedString(from: NSNumber(value: whatever), number: NumberFormatter.Style.decimal)

Upvotes: 43

arthankamal
arthankamal

Reputation: 6413

Why don't you limit the precision, like ".0f"

resultFV.text = String.localizedStringWithFormat("%.0f", fv)

Updated Answer:

var formatter: NSNumberFormatter = NSNumberFormatter()
formatter.numberStyle = NSNumberFormatterStyle.DecimalStyle;
var formattedStr: NSString = formatter.stringFromNumber(NSNumber(double: fv))!
resultFV.text = formattedStr

Upvotes: 4

Related Questions